The answer would be A. When using Cramer's Rule to solve a system of equations, if the determinant of the coefficient matrix equals zero and neither numerator determinant is zero, then the system has infinite solutions. It would be hard finding this answer when we use the Cramer's Rule so instead we use the Gauss Elimination. Considering the equations:
x + y = 3 and <span>2x + 2y = 6
Determinant of the equations are </span>
<span>| 1 1 | </span>
<span>| 2 2 | = 0
</span>
the numerator determinants would be
<span>| 3 1 | . .| 1 3 | </span>
<span>| 6 2 | = | 2 6 | = 0.
Executing Gauss Elimination, any two numbers, whose sum is 3, would satisfy the given system. F</span>or instance (3, 0), <span>(2, 1) and (4, -1). Therefore, it would have infinitely many solutions. </span>
Answer:
$11,728
Step-by-step explanation:
Twice a year, for 4 years is 8 times
516×8 = 4128
Yearly for 4 years is 4 times
700×4 = 2800
Every month for 4 years is 48 times
100×48 = 4800
Minimum expenditure:
4128 + 2800 + 4800 = $11,728
Answer:
29.95 mintues answer of this question
Answer:
two numbers divided to get 35
Step-by-step explanation:
