The characteristics of standing waves allows to find the result for the speed of the wave is:
- The speed wave is: v = 10 m / s
The wave is a way of transmitting energy without mass displacement, , in the attachment we can see a diagram of the standing wave.
Each cycle corresponds to half a wavelength, they indicate that the frequency is 2.50 Hz and there are three cycles, so the wavelength is:
L = 
λ = 2L/n
λ = 2 6 /3
λ = 4 m
Wave speed is related to wavelength and frequency
v = λ f
v = 4 2.5
v = 10 m / s
In conclusion, using the characteristics of standing waves we can find the result for the speed of the wave is:
- The wave speed is: v = 10 m / s
Learn more here: brainly.com/question/12536719
- Initial velocity (u) = 0 m/s [the car was at rest]
- Distance (s) = 80 m
- Time (t) = 10 s
- Let the magnitude of acceleration be a.
- By using the equation of motion,
we get,
<u>A</u><u>nswer:</u>
<u>The </u><u>magnitude</u><u> </u><u>of </u><u>its </u><u>acceleration</u><u> </u><u>is </u><u>1</u><u>.</u><u>6</u><u> </u><u>m/</u><u>s^</u><u>2</u><u>.</u>
Hope you could get an idea from here.
Doubt clarification - use comment section.
Answer;
-it will move away from the large ball because like charges repel.
Explanation;
-Electric force is the force that pushes apart two like charges, or that pulls together two unlike charges. The basic law of electrostatics Like charges of electricity repel each other, whereas unlike charges attract each other.
When small, positively charged ball is moved close to a large, positively charged ball it would be pushed away from the large positively charged ball since they are both positively charged. One has to put in energy to try to move the small ball closer to the large ball. The closer one try to move it to the large ball, the more energy one has to put in, so the more electrical potential energy the small ball would have.
The velocity is given by:
V = √(Vx²+Vy²)
V = velocity, Vx = horizontal velocity, Vy = vertical velocity
Given values:
Vx = 6m/s, Vy = 12m/s
Plug in and solve for V:
V = √(6²+12²)
V = 13.42m/s
Now find the direction:
θ = tan⁻¹(Vy/Vx)
θ = angle of velocity off horizontal, Vy = vertical velocity, Vx = horizontal velocity
Given values:
Vx = 6m/s, Vy = 12m/s
Plug in and solve for θ:
θ = tan⁻¹(12/6)
θ = 63.4°
The resultant velocity is 13.42m/s at an angle of 63.4° off the horizontal.
