Answer:
This is due to a relative decrease in atmospheric pressure in high places.
Explanation:
Given that atmospheric pressure decreases at the higher point or ground, this reduced atmospheric pressure, however, will be unable to contain the Mercury in the barometer tube.
Therefore, at the top of the mountain where the air pressure is low, the barometer reading ultimately goes down.
Hence, the level of mercury falls in a barometer while taking it to a mountain "due to a relative decrease in atmospheric pressure in high places."
When we hit the puck from tap the puck will move forward.
This is due to the impulse provided by us at the time of hit. Due to this impulse the puck will move forward and start moving in some direction.
As soon as puck move forward the force on it is zero as the weight of the puck is counterbalanced by the air stream force and there is no other force on it so puck will continue its motion till it will hit at some other point.
So here the motion of the puck will be uniform motion till it will collide with some other points.
So here the correct option will be given as
<em>moves with a constant speed until hitting the other end.</em>
Explanation:
The force is 186.5 N. 3.8% of the force is directed downward. So the vertical component of the force is:
Fᵧ = 0.038 (186.5 N)
Fᵧ = 7.087 N
The horizontal component is found with Pythagorean theorem:
F² = Fₓ² + Fᵧ²
(186.5 N)² = Fₓ² + (7.087 N)²
Fₓ = 186.4 N
So the work done is:
W = Fd
W = (186.4 N) (7.4 m)
W = 1379 J
Round as needed.
Answer:
Temperature is a physical property of matter that quantitatively expresses hot and cold
Explanation:
Answer:
The average velocity for the time period beginning when t=1 and lasting 0.1 seconds = 16.40 ft/s.
Explanation:
Given that the height of the ball at time t is

The average velocity of an object is defined as the total displacement covered by the particle divided by the total time taken in covering that displacement.
If
are the heights of the ball at time
and
, then the total displacement covered by the ball from time
to
is
.
Thus, the average velocity of the ball for the time interval
is given by

For the time interval, beginning when t = 1 second and lasting 0.1 seconds,
