Answer:
a) 24.43 radians per second
b) 268.73 inches per second
Explanation:
a) The angular speed of the fan on Celsius degrees/second is 1400, so we should convert that value to radians using the fact that 2π rad = 360 °C:


b) Linear speed on a point of the blade is related with angular speed of the fan by the equation

with v linear speed, ω angular speed and r the radius of the blades. So:

Radians isn't really a unity; it is dimensionless so we can put it or not. So:

The air pressure inside the balloon is: 0.1432 Pa
The formulas and procedures that we will use to solve this problem are:
Where:
- a = area of the sphere
- r = radius
- π = mathematical constant
- P = Pressure
- F = Force
- a = surface area
Information about the problem:
- r = 5.0 m
- F = 45 N
- 1 Pa = N/m²
- 1 N = kg * m/s²
- a=?
- P=?
Using the formula of the sphere area we get:
a = 4 * π * r²
a = 4 * 3.1416 * (5.0 m)²
a = 314.16 m²
Applying the pressure formula we get:
P = F/a
P = 45 N/314.16 m²
P = 0.1432 Pa
<h3>What is pressure?</h3>
It is a physical quantity that expresses the force applied on the area of a surface.
Learn more about pressure at: brainly.com/question/26269477
#SPJ4
Rest - it is the state in which body doesn’t move from it’s place
motion - it is the state in which body moves from it’s place
Complete Question:
Metal sphere A has a charge of − Q . −Q. An identical metal sphere B has a charge of + 2 Q . +2Q. The magnitude of the electric force on sphere B due to sphere A is F . F. The magnitude of the electric force on sphere A due to sphere B must be:
A. 2F
B. F/4
C. F/2
D. F
E. 4F
Answer:
D.
Explanation:
If both spheres can be treated as point charges, they must obey the Coulomb's law, that can be written as follows (in magnitude):

As it can be seen, this force is proportional to the product of the charges, so it must be the same for both charges.
As this force obeys also the Newton's 3rd Law, we conclude that the magnitude of the electric force on sphere A due to sphere B, must be equal to the the magnitude of the force on the sphere B due to the sphere A, i.e., just F.