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GrogVix [38]
3 years ago
5

The frequency of D3 is 146.83 Hz. What is the frequency of D5, which is two octaves above D3?

Mathematics
1 answer:
Vaselesa [24]3 years ago
5 0

Answer: D

Frequency = 587.32 Hz

Step-by-step explanation:

One octave above has a frequency of 2 × 146.83 Hz = 293.66Hz (D4). Two octaves above has afrequency of 2 × 293.66 Hz = 587.32 Hz (D5)

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Answer:

Part 2

The rate of change is 1 in increase in forearm length per 1 inch increase in foot length

Part 3

1) Foot length = 17.922 in.

2) The rate of change of the equation y = 0.860·x + 3.302 in part A is 0.860

3) No the data does not correspond with part A

4) The data  presented here has a greater rate of change

5) Different data sources

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Step-by-step explanation:

Part 2

The data are as follows

Forearm             Foot

9.25                    8.5

10.25                   9.5

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10.75                    10

8.75                       8

To find the rate of change, we have;

For points

(x₁, y₁) = (9.25, 8.5) and (x₂, y₂) = (8.75, 8) we have;

Rate of change = (y₂ - y₁)/(x₂ - x₁) substituting the values we arrive at

(8.75 - 9.25)/(8 - 8.5) = 1

The rate of increase of foot to forearm is 1 to 1. That is there is an increase of 1 in in forearm length for every inch increase in foot length

The rate of change is 1 in increase in forearm length per 1 inch increse in foot length

Part 3

1) For a person with length of forearm, x = 17 inches long, we have;

Length of foot, y = 0.860·x + 3.302

Plugging in the values, we have;

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2) The rate of change of the equation y = 0.860·x + 3.302 in part A is 0.860

3) No the data does not correspond with part A

4) The rate of change from part A = 0.860, Therefore, the data  presented here has a greater rate of change

5) The values are different because of they are derived from a non corresponding sources

6) Yes the relation is a function because the length of the foot is a function of the length of the forearm

From the equation of a straight line, we have;

y = mx + c

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m = Slope = 1

Therefore; for forearm, y = 9.25, we have

9.25 = 1×8.5 + c

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The equation of the function becomes;

y = x + 1

7) for the equation in part A given by

y = 0.860·x + 3.302

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