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3 years ago

Which is more, 10 grams or 12,000 milligrams

Mathematics

2 answers:

borishaifa [10]3 years ago

4 0

12,000 i dont just 12,000

Evgesh-ka [11]3 years ago

3 0

There are 1000 milligrams in 1 gram so,

12,000/1000=12 grams

12,000 milligrams is more

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Select the correct answer for each statement Will yield consecutive odd integers Will yield consecutive integers

Ivahew [28]

Complete question :

Select the correct answer for each statement.

1.) Will yield consecutive odd integers.

k+10, k+12, k+14

k+2, k+3, k+4

2.) Will yield consecutive integers.

k+1, k+2, k+3

k+6, k+8, k+10

Answer:

Consecutive odd integer : k+10, k+12, k+14

Consecutive integers : k+1, k+2, k+3

Step-by-step explanation:

Odd integers are numbers which aren't divisible by 2 ; such as : 1, 3, 5, 7, 9, 11,... The series continues in that manner. Consecutive odd integers have a common difference of 2, just as indicated in the instance given ; 1, 3, 5, 7, 9, 11,...

Therefore a series with a difference of 2 is more likely to be one representing consecutive odd integers.

2.) for concmsecutive integers :

Consecutive integers have a common difference of 1 between each successive integer ;

Hence, k+1, k+2, k+3 will most likely represent consecutive integers since the value of k is the same.

7 0

3 years ago

Determine the area of the composite figure.

rodikova [14]

Answer:

113 $m^{2}$

Step-by-step explanation:

top rectangle = l x w = 6 x 13 = 78

lower rectangle width = 13-8=5. so a = l x w. 7 5 = 35

78+35= 113

5 0

3 years ago

A population of rabbits is described by the function R(t) = 100(2t/5), where t is measured in months and R is measured in rabbit

Savatey [412]

Answer and Step-by-step explanation: The graph is shown in the attachment.

a. ΔR on [1,2] is mathematically expressed as:

ΔR = R(2) - R(1)

which means difference of population of rabbits after 2 months and after 1 month.

$R(1) = 100(\frac{2}{5}.1 )$

$R(1) = 100(\frac{2}{5} )$

R(2) = $100(\frac{2}{5}.2 )$

$R(2) = 100(\frac{4}{5} )$

$\Delta R = 100(\frac{4}{5} )-100(\frac{2}{5} )$

$\Delta R = 100[\frac{4}{5} - \frac{2}{5} ]$

$\Delta R=$ 40

Difference of rabbits between first and second months is 40.

b. R(0) = 100( $\frac{2}{5} .0$ )

R(0) = 0

Initially, there no rabbits in the population.

c. R(10) = $100(\frac{2}{5}.10 )$

R(10) = 400

In 10 months, there will be 400 rabbits.

d. R(t) = 500

$500=100(\frac{2}{5}.t )$

$\frac{500}{100}=\frac{2}{5}.t$

$t = \frac{500.5}{100.2}$

t = 12.5

In 12 and half months, population of rabbits will be 500.

3 0

3 years ago

Greatest common factor of 112 and 63

FrozenT [24]

Answer:

It's 7!

Step-by-step explanation:

6 0

3 years ago

Liza buys 4 yards of fabric for $8.48. How much was the fabric per yard?

levacccp [35]

Answer:

the fabric per yard was 2.12

Step-by-step explanation:

5 0

3 years ago

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