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koban [17]
3 years ago
11

Hi I need help! A chocolate is a natural resource Is it true or false? Thx

Physics
2 answers:
nikdorinn [45]3 years ago
5 0

Answer:

yes it's true

Explanation:

Cocoa is considered a natural resource because it grows on trees in the forms of cocoa beans. Growing cocoa is hard work and also has been used as a method of child labour. Another way in which people rely on cocoa is through the tasteful products created from it. Like chocolate or cocoa powder used in delicacies.

Reika [66]3 years ago
4 0
Technically yes Cocoa is considered a natural resource because it grows on trees in the forms of cocoa beans. Cocoa farming supplies the jobs for around 6 million people which make them rely on it. ... Like chocolate or cocoa powder used in delicacies.
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Two cars enter the Florida Turnpike at Commercial Boulevard at 8:00 AM, each heading for Wildwood. One car’s average speed is 10
olganol [36]

Answer:

The average speed of the cars is 50mph

Explanation:

Option C

4 0
3 years ago
A moving freight car runs into an identical car at rest on the track. The cars couple together. Compared to the velocity of the
Leno4ka [110]

Answer:

one half as large , initial velocity is two times larger

Explanation:

Momentum is conserved.

p₁ + p₂ = p₁' + p₂'

m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'

m₁ = m₂ =m , v₂= 0

v₁' =v₂'

mv₁ = 2mv₁'

v₁ = 2v₁'

8 0
3 years ago
A ball accelerates from rest down a ramp at 2.4 m/s^2. Write an equation that could be used to determine the balls finals positi
Alik [6]

Answer:

x=2.4t+4.9t^2

Explanation:

This equation is one of the kinematic equations to solve for distance. The original equation is as follows:

X=Xo+Vt+1/2at^2

We know that the ball starts at rest meaning that its initial velocity and position is zero.

X=0+Vt+1/2at^2

Since it is going down the ramp, you can use the acceleration of gravity constant. (9.81 m/s^2) and simplify that with the 1/2.

X=Vt+4.9t^2

Note: Since the positive direction in this problem is down, you are adding the 4.9t^2, but if a question says that the downward direction is negative, you would subtract those values.

Now, substitute in your velocity value.

X=2.4t+4.9t^2

8 0
2 years ago
You hang a heavy ball with a mass of 10 kg from a gold wire 2.6 m long that is 1.6 mm in diameter. You measure the stretch of th
PolarNik [594]

<u>Answer:</u> The Young's modulus for the wire is 6.378\times 10^{10}N/m^2

<u>Explanation:</u>

Young's Modulus is defined as the ratio of stress acting on a substance to the amount of strain produced.

The equation representing Young's Modulus is:

Y=\frac{F/A}{\Delta l/l}=\frac{Fl}{A\Delta l}

where,

Y = Young's Modulus

F = force exerted by the weight  = m\times g

m = mass of the ball = 10 kg

g = acceleration due to gravity = 9.81m/s^2

l = length of wire  = 2.6 m

A = area of cross section  = \pi r^2

r = radius of the wire = \frac{d}{2}=\frac{1.6mm}{2}=0.8mm=8\times 10^{-4}m      (Conversion factor:  1 m = 1000 mm)

\Delta l = change in length  = 1.99 mm = 1.99\times 10^{-3}m

Putting values in above equation, we get:

Y=\frac{10\times 9.81\times 2.6}{(3.14\times (8\times 10^{-4})^2)\times 1.99\times 10^{-3}}\\\\Y=6.378\times 10^{10}N/m^2

Hence, the Young's modulus for the wire is 6.378\times 10^{10}N/m^2

3 0
4 years ago
Yo, help will give brainliest
kaheart [24]

Answer:

30

Explanation:

30

6 0
3 years ago
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