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LekaFEV [45]
2 years ago
8

A ball accelerates from rest down a ramp at 2.4 m/s^2. Write an equation that could be used to determine the balls finals positi

on, assuming the positive direction points down the ramp.
Physics
1 answer:
Alik [6]2 years ago
8 0

Answer:

x=2.4t+4.9t^2

Explanation:

This equation is one of the kinematic equations to solve for distance. The original equation is as follows:

X=Xo+Vt+1/2at^2

We know that the ball starts at rest meaning that its initial velocity and position is zero.

X=0+Vt+1/2at^2

Since it is going down the ramp, you can use the acceleration of gravity constant. (9.81 m/s^2) and simplify that with the 1/2.

X=Vt+4.9t^2

Note: Since the positive direction in this problem is down, you are adding the 4.9t^2, but if a question says that the downward direction is negative, you would subtract those values.

Now, substitute in your velocity value.

X=2.4t+4.9t^2

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In the Biomedical and Physical Sciences building at MSU there are 135 steps from the ground floor to the sixth floor. Each step
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Answer:

W = 16.5 Kj

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E = 16471

Explanation:

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t = 5min 30sec = (5×60) + 30 = 330sec

each step = 16.6cm = 0.166m

h = 135×0.166 = 22.41 m

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(i) W = F × s = W × h = mgh

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(ii) Power = workdone/time

P = 16471.35/330

P = 49.9 Watt

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A solid sphere with a radius of 50.0 cm has a total positive charge of 40.0 μC uniformly distributed in its volume. Calculate th
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Answer:

E=2.88\times 10^5\ N/C                              

Explanation:

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Charge on the sphere, q=40\ \mu C=40\times 10^{-6}\ C

We need to find the magnitude of the electric field r = 10.0 cm away from the center of the sphere. The electric field at point r away form the center of the sphere is given by :

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E=\dfrac{9\times 10^9\times 40\times 10^{-6}\times 0.1}{0.5^3}

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So, the electric field 10.0 cm away from the center of the sphere is 2.88\times 10^5\ N/C. Hence, this is the required solution.              

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