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Vedmedyk [2.9K]
2 years ago
5

If a hot air balloon is seen rising above the top of a hill, what is the top of the hill called? Question 2 options: delta point

distance system coordinate system reference point.
Physics
1 answer:
timofeeve [1]2 years ago
5 0

If a hot air balloon has shown rising above the top of a hill, the top of the hill is considered as a reference point.

<h2>Reference Point:</h2>

It is a point that is used to standardize a experiment. The reference point is a constant point.

In the given problem:

  • The hot air balloon is rising above the top of the hill. Here, the hill is a standard point that has a fixed (constant) height.
  • Some other reference points are the top of the Eifel Tower or a famous shop which a person use to denote a certain distance.

Therefore, "If a hot air balloon has shown rising above the top of a hill" the top of the hill is considered as a reference point.

Learn more about Reference Point:

brainly.com/question/1674904

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A 5.0 kg block hangs from the ceiling by a mass-less rope. A Second block with a mass of 10.0 kg is attached to the first block
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The tension in the first and second rope are; 147 Newton and 98 Newton respectively.

Given the data in the question

  • Mass of first block; m_1 = 5.0kg
  • Mass of second block, m_2 =10kg
  • Tension on first rope; T_1 =\ ?
  • Tension on second rope; T_2 =\ ?

To find the Tension in each of the ropes, we make use of the equation from Newton's Second Laws of Motion:

F = m\ *\ a

Where F is the force, m is the mass of the object and a is the acceleration ( In this case the block is under gravity. Hence ''a" becomes acceleration due to gravity  g = 9.8m/s^2 )

For the First Rope

Total mass hanging on it; m_T = m_1 + m_2 = 5.0kg + 10.0kg = 15.0kg

So Tension of the rope;

F = m\ * \ g\\\\F = 15.0kg \ * 9.8m/s^2\\\\F = 147 kg.m/s^2\\\\F = 147N

Therefore, the tension in the first rope is 147 Newton

For the Second Rope

Since only the block of mass 10kg is hang from the second, the tension in the second rope will be;

F = m\ * \ g\\\\F = 10.0kg \ * 9.8m/s^2\\\\F = 98 kg.m/s^2\\\\F = 98N

Therefore, the tension in the second rope is 98 Newton

Learn More, brainly.com/question/18288215

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