500% of is 4,350.<br> (Type a whole number.)

The Mackinac Bridge in Michigan is the third-longest suspension bridge in the United States.

likoan [24]

A: 60.66 m
b:8.04 km

6 0

3 years ago

Read 2 more answers

The graph shows the side view of a water slide

GaryK [48]

Step-by-step explanation: Given that the graph shows the side view of a water slide with dimensions in feet.

We are to find the rate of change between the points (0, ?) and (?, 40).

From the graph, we note that

the y co-ordinate for the x co-ordinate 0 is 80 and the x co-ordinate for the y co-ordinate 40 is 5.

So, the given two points are (0, 80) and (5, 40).

The rate of change for a function f(x) between the points (a, b) and (c, d) is given by

Therefore, the rate of change for the given function between the points (0, 80) and (5, 40) is

Thus, the required rate of change is -8.

7 0

2 years ago

The vertex of the parabola below is at the point (1, 5), and the point (2, 8) is on the parabola. What is the equation of the pa

N76 [4]

Answer: B

Step-by-step explanation:

the parabola having (1,5) as vertex have as equation:

y=k*(x-1)²+5

It is passing through (2,8)

8=k*(2-1)²+5 ==> k+5=8 ==> k=3

equation is y=3(x-1)²+5

Answer B

6 0

2 years ago

1+1 abcdefghijklmnopqrstuvwxyandz

skad [1K]

Answer:2

Step-by-step explanation: two 1 equal one 2

3 0

3 years ago

Read 2 more answers

Assume that you have a sample of n 1 equals 6, with the sample mean Upper X overbar 1 equals 50, and a sample standard deviati

tigry1 [53]

Answer:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

$df=6+5-2=9$

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

$n_1 =6$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

$\bar X_1 =50$ represent the sample mean for the group 1

$\bar X_2 =38$ represent the sample mean for the group 2

$s_1=7$ represent the sample standard deviation for group 1

$s_2=8$ represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

We are assuming that the population variances for each group are the same

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic for this case is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

The pooled variance is:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

We can find the pooled variance:

$S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67$

And the pooled deviation is:

$S_p=7.46$

The statistic is given by:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

The degrees of freedom are given by:

$df=6+5-2=9$

The p value is given by:

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0

3 years ago

500% of is 4,350. (Type a whole number.)