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DedPeter [7]
3 years ago
6

Is 2y-x/6-4=0 a linear function

Mathematics
1 answer:
noname [10]3 years ago
3 0

A equation of a linear function in a standard form:

Ax + By = C

2y-\dfrac{x}{6}-4=0\ \ \ \ |\cdot(-6)\\\\-12y+x+24=0\ \ \ \ |-24\\\\-12y+x=-24\\\\\boxed{x-12y=-24}

<h3>Answer: YES. It's a linear function.</h3>
You might be interested in
two sides of a triangle are equal in length. the length of the third side is three more than the length of the equal sides. the
cluponka [151]

Answer:

each side is 31cm

Step-by-step explanation:

91/3=31

31+31+31=93

4 0
3 years ago
1948 Olympics
mash [69]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

               ⬆                ⬆                 ⬆

         Low IQR      Median       High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR  is average of 59.3 and 59.6 =  59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

                    ⬆                  ⬆                      ⬆

             Low IQR         Median          High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

Read more on Brainly.com - brainly.com/question/14915771#readmore

8 0
3 years ago
What is the value of x?<br> 12 units<br> 18<br> 15 units<br> 20 units<br> 24 units
Ierofanga [76]

Answer:

Step-by-step explanation:

Question

What is the value of x?

12 units

Answer:

Step-by-step explanation:18

15 units

20 units

24 units

5 0
3 years ago
Read 2 more answers
Find the arc length and area of a sector with radius R =60 inches and central angle equals 30° round your answer to the nearest
Black_prince [1.1K]

Answer:

(a)31.42 inches

(b)942.48 Square Inches

Step-by-step explanation:

Given a sector of a circle with the following dimensions:

Radius of the circle =60 inches

Central Angle of the sector =30°

(a)Arc Length

Arc Length =\dfrac{\theta}{360^\circ}X2\pi r

=\dfrac{30}{360^\circ}X2*60*\pi\\\\=10\pi\\\\=31.42$ Inches (correct to the nearest hundredth)

(b)Area of the sector

Area of the sector =\dfrac{\theta}{360^\circ}X\pi r^2

=\dfrac{30}{360^\circ}X\pi*60^2\\\\=300\pi\\\\=942.48$ Square Inches (correct to the nearest hundredth)

3 0
3 years ago
Read 2 more answers
A car travels at the rate of x miles per hour for y minutes. which of the following gives the number of miles the car has travel
harkovskaia [24]

Given that speed of car = x miles per hour

Time of travel = y minutes = y/60 hours

(Because there are 60 minutes in an hour)

We have to calculate distance travelled so we will use formula

Distance = speed * time

Distance = x * y/60

Distance = xy/60

Hence choice d) xy/60 is the final answer.

7 0
3 years ago
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