<h3>Question:</h3>
<em>Jon is selling tickets for the school talent show. On the 1st day, he sold 3 senior tickets and 12 child tickets for $195. On the 2nd day he sold 13 senior tickets for $299. Find the price of a senior citizen ticket.</em>
<h3>Answer:</h3>
Create a system of equations to help you solve this problem. The system of equations will look like: 3s + 12c = 195 and 13s = 299. The variable s represents the cost of senior tickets and the variable c represents the cost of children tickets.

Solve the second equation for the variable s as this is the easiest way to solve the problem. Solve the second equation for s by dividing both sides of the equation by 13 to isolate the variable s.
s = 23
Since the question was only asking for the price of a senior citizen ticket, you are technically done. The first equation was only put there to confuse you or allow you to check your work if you needed to. The price of a senior citizen ticket (variable s) is $23.
Answer:
First, subtract to find the amount of change: 225 - 25 = 200. The increase is 25. Next, divide the amount of change by the original amount:.
Step-by-step explanation:
W= width
l= length= 2w-3
Area= length * width
A= lw
substitute l=2w-3 for l
54= (2w-3)(w)
54= 2w^2 - 3w
subtract 54 from both sides
0= 2w^2 - 3w - 54
factor the polynomial
0= (2w + 9)(w - 6)
Set each set of parentheses equal
to 0 and solve for width.
0=2w+9
-9=2w
-4.5= w NEGATIVE VALUE
0=w-6
6 cm=w
-4.5 is not the answer because it has a negative value. You cannot have a negative side of a photograph. So substitute 6 in to find length.
length= 2w-3
l= 2(6)-3
l= 12-3
l= 9 cm
CHECK:
w= 6cm
l= 9cm
Area= length * width
54= 6*9
54= 54
ANSWER: width= 6cm; length= 9cm
Hope this helps! :)
Answer:
102 is the correct answet