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Keith_Richards [23]

3 years ago

6

A bookstore charges $4 for shipping, no matter how many books you buy. Irena makes a graph showing the shipping cost for I to 5

books. She claims that the points she graphed lie on a line. Does her statement make sense? Explain

1 answer:

mihalych1998 [28]3 years ago

4 0

Answer:

can we see the graph?

Step-by-step explanation:

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Use the graphing calculator to graph the quadratic function y=2x^2 + 2x -40. what are the zeros of the function

ahrayia [7]

Answer:

The zeroes of this function are x=-5 and x=4

3 0

3 years ago

What is the prime factorization of 40?<br> 1. 2x5<br> 2. 2x20<br> 3. 2x2x2x5<br> 4. 2x2x4x5

noname [10]

Answer: number 3 is the answer

3 0

3 years ago

Read 2 more answers

Simplify the rational expression. state any restrictions on the variable. n^4-11n^2+30/n^4-7n^2+10

Andrej [43]

<span>For this case we have the following expression:
</span> $\frac{n ^ 4-11n ^ 2 + 30}{ n ^ 4-7n ^ 2 + 10} 

$
<span> We are going to make the following change of variables:
</span> $x = n ^ 2
$
<span>Rewriting the expression we have:
</span> $\frac{(x ^ 2-11x + 30)}{(x ^ 2-7x + 10)} 

$
<span>Factoring the expression we have:
</span> $\frac{(x-5) (x-6)}{(x-5) (x-6)} 
$
<span>Canceling similar terms we have:
</span> $\frac{x-6}{x-2} 
$
<span>Returning the change we have:
</span> $\frac{n ^ 2-6}{n ^ 2-2} 

$
<span> The resctrictions of the function are those that make the denominator equal to zero.
We have then:
</span> $n ^ 2-2 = 0

n = +/- \sqrt{2} 
$
<span> Answer:
The simplified expression is:
</span> $\frac{n ^ 2-6}{n ^ 2-2}$
<span>The restrictions are:
</span> $n = \sqrt{2} 
$
$n = - \sqrt{2}$

7 0

3 years ago

F (x + 5) - 2(4x - 1) = 0, what is the value of x?

schepotkina [342]

It is a.1

(1+5) - 2(4(1)-1) = 0

(6) - 2(3) = 0

6 - 6 = 0

0=0

4 0

3 years ago

Write a quadratic function, in standard form, that fits the set of points. Solve it as a system of three equations. (-4, 9), (0,

Tresset [83]

Answer:

$\boxed{y=2x^2+4x-7}$

Step-by-step explanation:

Let the quadratic function be

$y=ax^2+bx+c$

We substitute $(-4,9)$ into the equation to obtain;

$9=a(-4)^2+b(-4)+c$

$\Rightarrow 9=16a-4b+c---(1)$

We substitute $(0,-7)$ to obtain;

$-7=a(0)^2+b(0)^2+c$

$\Rightarrow c=-7---(2)$

We finally substitute $(1,-1)$ to obtain;

$-1=a(1)^2+b(1)^2+c$

$\Rightarrow -1=a+b+c---(3)$

We put equation (2) into equation (1) to get;

$9=16a-4b-7$

$16a-4b=16$

$\Rightarrow 4a-b=4---(4)$

$\Rightarrow -1=a+b-7$

$\Rightarrow a+b=6---(5)$

We add equation (4) and (5) to get;

$4a+a=6+4$

$\Rightarrow 5a=10$

$\Rightarrow a=2$

We put $a=2$ into equation (5) to get;

$2+b=6$

$\Rightarrow b=6-2$

$\Rightarrow b=4$

The reqiured quadratic function is

$y=2x^2+4x-7$

7 0

3 years ago