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AnnZ [28]
3 years ago
6

Find the midpoint of the segment having endpoints at (3, 6) and (-1, 2).

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
7 0

Answer:

The midpoint is (1,4)

Step-by-step explanation:

To find the midpoint

Add the x coordinates together and divide by 2

(x1+x2)/2 = (3+-1)/2 = 2/2 =1

Add the y coordinates together and divide by 2

(y1+y2)/2 = (6+2)/2 = 8/2 =4

The midpoint is (1,4)

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We see that 90+8=98 degrees.

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The graph below represents cans collected for a food drive at willowdale middle
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1. The mechanics at Lincoln Automotive are reborning a 6 in deep cylinder to fit a new piston. The machine they are using increa
Firdavs [7]

Answer:

0.0239\frac{in^{3}}{min}

Step-by-step explanation:

In order to solve this problem, we must start by drawing a diagram of the cylinder. (See attached picture)

This diagram will help us visualize the problem better.

So we start by determining what data we already know:

Height=6in

Diameter=3.8in

Radius = 1.9 in (because the radius is half the length of the diameter)

The problem also states that the radius will increase on thousandth of an inch every 3 minutes. We can find the velocity at which the radius is increasing with this data:

r'=\frac{1/1000in}{3min}

which yields:

r'=\frac{1}{3000}\frac{in}{min}

with this information we can start solving the problem.

First, the problem wants us to know how fast the volume is increasing, so in order to find that we need to start with the volume formula for a cylinder, which is:

V=\pi r^{2}h

where V is the volumen, r is the radius, h is the height and π is a mathematical constant equal approximately to 3.1416.

Now, the height of the cylinder will not change at any time during the reborning, so we can directly substitute the provided height, so we get:

V=\pi r^{2}(6)

or

V=6 \pi r^{2}

We can now take the derivative to this formula so we get:

\frac{dV}{dt}=2(6)\pi r \frac{dr}{dt}

Which simplifies to:

\frac{dV}{dt}=12\pi r \frac{dr}{dt}

We can now substitute the data provided by the problem to get:

\frac{dV}{dt}=12\pi (1.9) (\frac{1}{3000})

which yields:

\frac{dV}{dt}=0.0239\frac{in^{3}}{min}

3 0
3 years ago
Find the average rate of change of f(x) = 4x² – 3 from 3 to 9.
Lina20 [59]

Answer:

44

Step-by-step explanation:

Given:

f(x) = 4x^2 - 3

Required:

Average range of change from 3 to 9

SOLUTION:

Step 1:

Find f(3) and f(9):

To find f(3), replace x with 3 in the given function

f(3) = 4(3)^2 - 3

f(3) = 4(9) - 3

f(3) = 36 - 3

f(3) = 33

To find f(9), replace x with 9 in the given function

f(9) = 4(9)^2 - 3

f(9) = 4(81) - 3

f(9) = 324 - 3

f(9) = 321

Average rate of change = \frac{f(b) - f(a)}{b - a}

Where,

a = 3, f(a) = 33

b = 9, f(b) = 321

Plug in the values into the formula for average rate of change.

= \frac{321 - 33}{9 - 3}

= \frac{288}{6}

= 44

Average rate of change = 44

3 0
3 years ago
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