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kirill [66]
2 years ago
14

Can you answer this pleas

Mathematics
2 answers:
grigory [225]2 years ago
6 0

Answer:

do 28 divided by 4 then add two zeros

MaRussiya [10]2 years ago
5 0

Answer:

700 kilograms

Step-by-step explanation:

2800 kilograms divvied up among 4 trucks can be:

2800/4

700 kilograms

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What's the Error? Explain the error. Find the correct solution.<br>19 + (-31) = 12​
Alex

Answer:

The answer is incorrect because 12 should be negative not positive.

Step-by-step explanation:

1. 19 + -31 = - 12

2. Twelve is negative because if you were to start off at -31 and add 19 the answer would remain negative since -31 in a sense is "bigger" than 19. You would need more of a positive number to make -31 positive such as 40.

40+ -31 = 9

5 0
3 years ago
If two angles in a triangle are 60° and 30°, is the third angle acute, obtuse, or right?​
Sindrei [870]

Answer: Right Angle

Step-by-step explanation:

And Since The Angles Of a Trangle Add Up To 180° When You Substract 90 From It You Remain With Another 90° Which Means The Angle Is Non Other Than a right angle traingle

60° + 30° = 90°

180° - 90° = 90°

∴ 90° = Right Angle Traingle

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3 years ago
Y-(-4)=-3[x-(2)] I'm looking for the slope intercept form of y
skad [1K]
Y+4=-3(x-2)
y+4=-3x+6
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8 0
3 years ago
What can you tell about the average number of dogs treated by each veterinarian in the past year
igor_vitrenko [27]

Answer: it's not D i thought it was and I got it WRONG!!!

7 0
2 years ago
Read 2 more answers
An urn contains three red balls and four blue balls. Draw two balls at random from the urn, without replacement. Compute the exp
mezya [45]

Step-by-step explanation:

in total we have 3+4 = 7 balls.

when we draw the first ball, the probability to draw a red ball is 3/7, and a blue ball 4/7.

when we draw the second ball, we have now only 6 balls in total.

the probabilty to draw a red back now depends also on the result of the first draw.

if the first ball was already red, then we have only a chance now of 2 out of 6.

if the first ball was blue, then we have now a chance of 3 out of 6.

so, the probably to draw at least 1 red ball in 2 draws is the probability of drawing one on the first draw plus the probability of drawing one on the second :

1 - probability to see 2 blue balls

1 - 4/7 × 3/6 = 1 - 12/42 = 30/42 = 0.714285714...

the expected number of red balls in 2 draws is

1 red in first red in first red in second

but not second and second but not first

1×(3/7 × 4/6) + 2×(3/7 × 2/6) + 1×(4/7 × 3/6) = 12/42 + 12/42 + 12/42 = 36/42 = 6/7 = 0.857142857 ≈ 0.8571

7 0
2 years ago
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