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3 years ago

Write three equations whose graphs are the same line as the equation 3x+2y=7

Mathematics

1 answer:

Zina [86]3 years ago

7 0

Answer:

y= -3/2x + 7

Step-by-step explanation:

so you start with 3x + 3 =7, then you subtract the 3x, bringing it to the other side with the 7. making it (-3x). Then all you have remaining on your left side is 2y. as shown: 2y=-3x +7, then all you have is divide by two. you do this because the opposite of multiplication is division. and 2y really means 2 x y. which gives you y= -3/2x + 7

hope this helped.

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Please help me out, someone. Please answer correctly. Remember I can report u

Murljashka [212]

When writing a number in scientific notation the first factor must have a value greater than or equal to one but less than 10.

3 0

3 years ago

The difference between two numbers is 10. The smaller number is 8.

Lunna [17]

Answer:

x - 8 = 10

Step-by-step explanation:

The smallest number is 8 so it's subtracting 8. 10 is the difference between the two numbers because it's the answer.

4 0

3 years ago

The sum of 5 consecutive integers is 200. What is the fourth number in this sequence.

babunello [35]

STEP-BY-STEP SOLUTION:

Let the smallest integer of the five integers = x

x + x + 1 + x + 2 + x + 3 + x + 4 = 200

5x + 10 = 200

5x = 200 - 10

5x = 190

x = 190 / 5

x = 38

Therefore:

Number no. 4 = x + 3 = 38 + 3 = 41

FINAL ANSWER:

Hence, the fourth number in the sequence is 41.

Please mark as brainliest if you found this helpful! :)
Thank you and have a lovely day! <3

7 0

4 years ago

Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

5 0

3 years ago

You and your friend are painting the walls in your apartment. You estimate that there is 1000 square feet of space to be painted

leva [86]

After 45 minutes you will have painted 4*45=180 square feet.

so the total number of painted area, y, is:

y=180+x*(3+4) after the 45 minutes

where x is the number of minutes AFTER THE 45 minutes:

if y is 1000 then

1000=180+x*7
820=x*7
x=117.14

so 117 minutes, or one hour and 57 minutes.

5 0

3 years ago