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navik [9.2K]
3 years ago
6

Suppose line segment AB has one endpoint at A(0, 0). What are the coordinates of B if (5, 3) is 1/3 of the way from A to B?

Mathematics
1 answer:
prisoha [69]3 years ago
5 0

Answer:

B(x_2,y_2)= (20,12)

Step-by-step explanation:

Given

A = (0,0)

Ratio; m : n = 1 : 3

Point\ at\ 1 : 3 = (5,3)

Required

Coordinates of B

This question will be answered using line ratio formula;

(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})

In this case:

(x,y) = (5,3)

(x_1,y_1) = (0,0)

m : n = 1 : 3

Solving for (x_2,y_2)

(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n}) becomes

(5,3) =  (\frac{1 * x_2 + 3 * 0}{1 + 3},\frac{1 * y_2 + 3 * 0}{1 + 3})

(5,3) =  (\frac{x_2 + 0}{4},\frac{y_2 + 0}{4})

(5,3) =  (\frac{x_2}{4},\frac{y_2}{4})

Comparing the right hand side to the left;

\frac{x_2}{4} = 5 -- (1)

\frac{y_2}{4} = 3 -- (2)

Solving (1)

x_2 = 5 * 4

x_2 = 20

Solving (2)

y_2 = 3 * 4

y_2 = 12

Hence;

B(x_2,y_2)= (20,12)

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Answer:

Step-by-step explanation:

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Find the 12th term of the geometric sequence 5, -25, 125, ...5,−25,125,...
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Answer:

  • a_{12}=-244140625

Step-by-step explanation:

Considering the geometric sequence

5,-25,\:125,\:...

a_1=5

As the common ratio 'r' between consecutive terms is constant.

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}

r=\frac{-25}{5}=-5

r=\frac{125}{-25}=-5

The general term of a geometric sequence is given by the formula:  

a_n=a_1\cdot \:r^{n-1}

where a_1 is the initial term and r the common ratio.

Putting n = 12 , r = -5 and a_1=5 in the general term of a geometric sequence to determine the 12th term of the sequence.

a_n=a_1\cdot \:r^{n-1}

a_n=5\left(-5\right)^{n-1}

a_{12}=5\left(-5\right)^{12-1}

      =5\left(-5^{11}\right)

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

       =-5\cdot \:5^{11}

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

        =-5^{1+11}     ∵ 5\cdot \:5^{11}=\:5^{1+11}

        =-244140625

Therefore,

  • a_{12}=-244140625
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