All categories

3 years ago

An object is located 10.0 cm from a convex mirror. The magnitude of the

Physics

1 answer:

Sunny_sXe [5.5K]3 years ago

6 0

Answer:

B. 6.00 cm

Explanation:

You might be interested in

A type O star is likely to appear _____. yellow, blue, green or red

Murljashka [212]

A type O star is likely to appear blue.

5 0

3 years ago

Read 2 more answers

Compare the magnitude of the magnetic field at the center of a circular current loop of radius 30 mm with the magnitude of the m

NISA [10]

Answer:

Ratio of magnetic field will be $\frac{B}{B'}=0.0055$

Explanation:

We have given radius of the loop r = 30 mm = 0.03 m

We know that magnetic field at the center of the loop is given by

$B=\frac{\mu _0i}{2r}$ ---------eqn 1

Number of turns in the solenoid is given as n = 3 turn per mm = 3000 turn per meter

We know that magnetic field due to solenoid is given by

$B'=n\mu _0i$ -------------eqn 2

Now dividing eqn 1 by eqn 2

$\frac{B}{B'}=\frac{\frac{\mu _0i}{2r}}{\mu _0ni}=\frac{1}{2nr}=\frac{1}{2\times 3000\times 0.03}=0.0055$

4 0

4 years ago

Two cars A and B are moving with velocities 20 m/s and 15 m/s in the direction east and west respectively. If

Sphinxa [80]

Answer:

Distance between them is 4,200 meters.

Explanation:

Consinder car A:

${ \bf{distance = speed \times time }}$

substitute:

$distance = 20 \times (2 \times 60) \\ = 2400 \: m$

Consider car B:

$distance = 15 \times (2 \times 60) \\ = 1800 \: m$

since these cars move in opposite directions, distance between them is their summation:

$distance \: between = { \sum(distance \: of \: each \: car)} \\ = 2400 + 1800 \\ = 4200 \: m$

3 0

3 years ago

g Two radiation modes (one at the center frequency lIo and the other at lIO+?lI) are excited with 1000 photons each. Determine t

Schach [20]

Answer:

a) P=0.25x10^-7

b) R=B*N2*E

c) N=1.33x10^9 photons

Explanation:

a) the spontaneous emission rate is equal to:

1/tsp=1/3 ms

the stimulated emission rate is equal to:

pst=(N*C*o(v))/V

where

o(v)=((λ^2*A)/(8*π*u^2))g(v)

g(v)=2/(π*deltav)

o(v)=(λ^2)/(4*π*tp*deltav)

Replacing values:

o(v)=0.7^2/(4*π*3*50)=8.3x10^-19 cm^2

the probability is equal to:

P=(1000*3x10^10*8.3x10^-19)/(100)=0.25x10^-7

b) the rate of decay is equal to:

R=B*N2*E, where B is the Einstein´s coefficient and E is the energy system

c) the number of photons is equal to:

N=(1/tsp)*(V/C*o)

Replacing:

N=100/(3*3x10^10*8.3x10^-19)

N=1.33x10^9 photons

7 0

3 years ago

How many turns are needed in a solenoid of radius 10 cm and length 20 cm for its self-inductance to be 6.0 H?

MA_775_DIABLO [31]

Answer:

Explanation:

5 0

3 years ago