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hoa [83]
2 years ago
7

What are 5 uses of reflection?

Physics
2 answers:
dangina [55]2 years ago
8 0
Optomety-contact/corrective lenses
binoculars periscopes and refracting telescopes and refracting telescopes
mangnifying glass
knowledge of refraction creates the most sparkly diamonds
prisms to divdide white light into it's into  it's component colours
certain optical illusions

Gre4nikov [31]2 years ago
3 0
<span>here u go!
fiber-Optics
Mirrors
Sonar
Radar
Study of seismic waves </span>
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Since the universe is infinite, the probability of events and reoccurrence is infinite. So that means that there is a chance, if
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Answer:

That insane it might be true because  a planet sometimes quoted to be an Earth 2.0 or Earth's Cousin based on its characteristics; also known by its Kepler Object of Interest designation KOI-7016.01) is an exoplanet orbiting the Sun-like star Kepler-452 about 1,402 light-years (430 pc) from Earth in the constellation Cygnus.

Explanation:

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2 years ago
17. (16 pts) You set up a two-slit experiment with a laser that produces light with a
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when the two waves interfere with eachother to make a dark spot the periodic difference of the two waves is π . the wave length for 2π is 600nm

. ie. for π difference it is 300nm

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3 years ago
What is the force of gravity (from the Earth) on the 700kg satellite if it’s 10km above the Earths surface?
joja [24]

Answer:

The force of gravity on a 700 kg satellite if its 10 km above Earth's surface is given by

    = {\frac{(6.674\times 10^{-11}N. m^2/kg^2)(5.97\times 10^{24}kg) }{(10\times10^3)^2} = 3984378 m / s^{2}

Explanation:

The force of gravity on a 700 kg satellite if its 10 km above Earth's surface is given by

    = {\frac{(6.674\times 10^{-11}N. m^2/kg^2)(5.97\times 10^{24}kg) }{(10\times10^3)^2} = 3984378 m / s^{2}

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3 years ago
1. What could scientists learn by using the Law of Superposition?
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Answer C. 1.scientists learn by using the law of superposition B
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Students in an introductory physics lab are performing an experiment with a parallel-plate capacitor made of two circular alumin
Alex777 [14]

Answer:

0.92 μC

Explanation:

In a parallel-plate capacitor, the electric field formed is equal to the charge density divited by the vacuum permisivity e0, as there are no dielectric between the plates. e0 is equal to 8.85*10^-12 C^2/Nm^2. The charge density is the total charge of each individual plate divided by its area. Then, the maximum charge allowed will be equal to:

E = \frac{o}{e_0} = \frac{Q}{Ae_0} \\ Q = E*A*e_0 = 3*10^6 N/C * (0.25*\pi *(0.21m)^2)*8.85*10^{-12}C^2/Nm^2 = 9.196 *10^{-7} C

or 0.92 μC

7 0
3 years ago
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