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Taya2010 [7]
3 years ago
8

Find the power required to give a brick 60 j of potential energy in a time of 3.0 s .

Physics
1 answer:
Radda [10]3 years ago
5 0
The calculation for power is
P = E / t
Where E is total energy transfered and t is time.
Now just substitute the number in
Power = 60 / 3
= 20W
The answer is 20W
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A cylindrical capacitor has an inner conductor of radius 2.7 mmmm and an outer conductor of radius 3.1 mmmm. The two conductors
Mars2501 [29]

Answer:

(A) Capacitance per unit length = 4.02 \times 10^{-10}

(B) The magnitude of charge on both conductor is Q = 4.22 \times 10^{-19} C and the sign of charge on inner conductor is +Q and the sign on outer conductor is -Q

Explanation:

Given :

Radius of inner part of conductor  (R_{1}) = 2.7 \times 10^{-3} m

Radius of outer part of conductor  (R_{2}) = 3.1 \times 10^{-3} m

The length of the capacitor (l) = 3 \times 10^{-3} m

(A)

Capacitance is purely geometrical property. It depends only on length, radius of conductor.

From the formula of cylindrical capacitor,      

     C = \frac{2\pi\epsilon_{o} l }{ln\frac{R_{2} }{R_{1} } }

Where, \epsilon_{o} = 8.85 \times 10^{-12}

But we need capacitance per unit length so,

     \frac{C}{l}  = \frac{2\pi\epsilon_{o}  }{ln\frac{R_{2} }{R_{1} } }

capacitance per unit length = \frac{6.28 \times 8.85 \times 10^{-12} }{ln(1.148)} = 4.02 \times 10^{-10}

(B)

The charge on both conductors is given by,

     Q = C \Delta V

Where, C = capacitance of cylindrical capacitor and value of C = 12.06 \times 10^{-13} F, \Delta V = 350 \times 10^{-3} V

∴ Q = 4.22 \times 10^{-19} C

The magnitude of charge on both conductor is same as above but the sign of charge is different.

Charge on inner conductor is +Q and Charge on outer conductor is -Q.

8 0
3 years ago
In the flow past a compression corner, the upstream Mach number and pressure are 3.5 and 1 atm, respectively. Downstream of the
yulyashka [42]

Answer:

\theta=23.7^{\circ}

Explanation:

The ratio of pressure 2 to 1 us 5.48/1= 5.48 rounded off as 5.5.

Referring to table A.2 of modern compressible flow then M_{\beta_1}=2.2

Also

M_{\beta_1}=M_1 sin \beta and making sin\beta the subject of the formula then

sin\beta=\frac {2.2}{3.5}\\\beta=38.94^{\circ}

Making reference to \theta-\beta-M diagram then

\theta=23.7^{\circ}

4 0
3 years ago
Hello people ~<br>Sound cannot travel through<br>(a) air<br>(b) water<br>(c) air<br>(d) vacuum​
SVETLANKA909090 [29]

Answer:

Vaccum

Explanation:

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You can test it .

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1 year ago
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Most of the sun's radiation passes through Earth's atmosphere and is absorbed by land and water. The diagram below shows some of
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B.The sunsu rediation C
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2 years ago
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A 30.0 kg packing case is initially at rest on the floor of a 1500 kg pickup truck. The coefficient of static friction between t
alexgriva [62]

Answer:

(a). The magnitude of the frictional force acting on the case is 66 N northward.

(b). The magnitude of the friction force acting on the case is 58.8 N southward.

Explanation:

Given that,

Mass of packing case = 30.0 kg

Mass of truck = 1500 kg

Coefficient of static friction = 0.30

Coefficient of kinetic friction = 0.20

Acceleration = 2.20 m/s² northward

(A). We need to calculate the force acting on the case

Using formula of force

F=ma

Put the value into the formula

F=30.0\times2.20

F=66\ N

We need to calculate the maximum static frictional force

Using formula of frictional force

f_{\mu}=\mu mg

Put the value into the formula

F_{\mu}=0.30\times30.0\times9.8

F_{\mu}=88.2

The frictional force is greater then the force acting on the block

Then, The frictional force is 66 N northward.

(B). We need to calculate the force acting on the case

Using formula of force

F = ma

Put the value into the formula

F=30.0\times3.40

F=102\ N

The static friction force is less then the force action on the case

We need to calculate the maximum static frictional force

Using formula of frictional force

f_{\mu}=\mu mg

f_{\mu}=0.20\times30.0\times9.8

f_{\mu}=58.8\ N

So, The magnitude of the friction force acting on the case is 58.8 N southward.

Hence, This is the required solution.

7 0
3 years ago
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