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valentinak56 [21]
3 years ago
13

Calculate the force applied to a car with mass of 1200 kg that has an acceleration of 2 m/s/s.

Chemistry
1 answer:
bearhunter [10]3 years ago
6 0

Answer:

2,400

Explanation:

F = m × a

F = 1200 × 2

F = 2,400

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3 years ago
An alien civilization has different names and symbols for six elements. Place each element in the correct location in the period
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Answer:

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Explanation:

3 0
3 years ago
Read 2 more answers
What are the answers to these?
antiseptic1488 [7]

Answer: 1. AgF + CaCl2 = AgCl + CaF2

2. C2H4 +O2 = CO2 +H2O

3. K2S = K+S

4. O2 + Mg = MgO

5. Mg + AlBr3 = MgBr2 + Al

6.C2H6O + O2= CO2 + H2O

7.Li2SO4 + MgCl2= Li2SO4 + MgCl2

8.HCl + Zn= H2 + ZnCl2

Explanation:

Balance the equation

Write down your given equation.

Write down the number of atoms per each element that you have on each side of the equation.

Always leave hydrogen and oxygen for last.

If you have more than one element left to balance:

Add a coefficient to the single carbon atom on the right of the equation to balance it with the 3 carbon atoms on the left of the equation.

Balance the hydrogen atoms next.

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4 0
3 years ago
Red #40 has an acute oral LD50 of roughly 5000 mg dye/1 kg body weight. This means if you had a mass of 1 kg, ingesting 5000 mg
FrozenT [24]

Answer:

350 g dye

0.705 mol

2.9 × 10⁴ L

Explanation:

The lethal dose 50 (LD50) for the dye is 5000 mg dye/ 1 kg body weight. The amount of dye that would be needed to reach the LD50 of a 70 kg person is:

70 kg body weight × (5000 mg dye/ 1 kg body weight) = 3.5 × 10⁵ mg dye = 350 g dye

The molar mass of the dye is 496.42 g/mol. The moles represented by 350 g are:

350 g × (1 mol / 496.42 g) = 0.705 mol

The concentration of Red #40 dye in a sports drink is around 12 mg/L. The volume of drink required to achieve this mass of the dye is:

3.5 × 10⁵ mg × (1 L / 12 mg) = 2.9 × 10⁴ L

8 0
3 years ago
Why do elements have different<br> properties?
Ann [662]
I think because each element has its own number of protons and neutrons, giving it its own atomic number and mass (correct me if I’m wrong please)
3 0
2 years ago
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