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umka2103 [35]
3 years ago
10

What is the concentration of NaCI in an aqueous solution that contains 0.032 grams of NaCI in 600. Grams of the solution

Chemistry
1 answer:
jolli1 [7]3 years ago
8 0

Answer:

0.00032 Grams of NaCl per 1 gram of the solution

Explanation:

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Sugar can be removed from a sugar water solution through dialysis.
Fantom [35]

Answer:

false

which I think

I am not sure

4 0
3 years ago
A rock weighing 30.0g is placed in a graduated cylinder displacing the volume from 22.3 ml to 27.6ml. what is density of the roc
Slav-nsk [51]
Density=mass / volume

Data:
mass=30.0 g
volume=volume with rock - volume without rock=27.6 ml - 22.3 ml=5.3 ml

1 ml=cm³  ⇒ 5.3 ml=5.3 cm³

Therefore:

Density=30.0 g / 5.3 cm³=5.66 g/cm³


Answer: density = 5.66 g/cm³
7 0
3 years ago
What are the properties of metal that make it a useful material for electricians?
Llana [10]
<span>Metal conducts electricity, which makes it useful for electricians. Additionally, certain types of metal such as metal wire are flexible and can be manipulated and bent easily by the electrician. Finally, many types of metal are widely available for purchase in stores at a reasonable cost.</span>
7 0
4 years ago
A sprinter set a high school record in track and field, running 200.0 m in 21.7 s . What is the average speed of the sprinter in
Yuliya22 [10]

Given data:

Distance travelled (d)= 200.0 m

Time taken (t) = 21.7 s

To determine:

The average speed in km/hr

Calculation:

Convert distance from m to km

1000 m = 1 km

200.0 m = 1 km * 200.0 m/1000 m = 0.2 km

Convert time from sec to hours

3600 sec = 1 hour

21.7 sec = 1 hour * 21.7 sec/3600 sec = 6.027 *10^-3 hrs

Speed is defined as the amount of distance travelled per unit time

Speed = distance/time = 0.2 km/6.027*10^-3 hr

           = 33.18 km/hr (or 33.2 km/hr)

7 0
3 years ago
When heated, calcium carbonate decomposes according to the equation given below:
Ahat [919]

Answer:

15.2L at STP

Explanation:

Given reaction expression;

         CaCO₃ → CaO + CO₂

Number of moles of CaCO₃  = 0.68mol

Unknown:

Volume of CO₂ produced at STP = ?

Solution:

To solve this problem, we must first find the number of moles CO₂ produced,

     1 mole of CaCO₃ will produce 1 mole of CO₂

   0.68mole of CaCO₃ will produce 0.68mole of CO₂ at STP

Now;

             1 mole of gas occupies a volume of 22.4L at STP;

           0.68mole of CO₂ will then occupy 0.68 x 22.4  = 15.2L at STP

8 0
3 years ago
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