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umka2103 [35]
3 years ago
10

What is the concentration of NaCI in an aqueous solution that contains 0.032 grams of NaCI in 600. Grams of the solution

Chemistry
1 answer:
jolli1 [7]3 years ago
8 0

Answer:

0.00032 Grams of NaCl per 1 gram of the solution

Explanation:

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One method of removing phosphate from wastewater effluents is to precipitate it with aluminum sulfate. A plausible stoichiometry
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Answer: The equation is written below.

Explanation:

2PO_4^{3-}(aq)+Al_2(SO_4)_3(aq)\rightarrow 2AlPO_4(s)+3SO_4^{2-}(aq)

According to Stoichiometry of the reaction:

2 moles of phosphate ions reacts with 1 mole of aluminum sulfate to produce 2 moles of aluminum phosphate precipitate and 3 moles of sulfate ions.

Aluminum phosphate is an odorless and white crystalline solid

The chemical equation is written above.

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3 years ago
If 8 g of ammonium hydroxide is completely decomposed by the reaction below in a closed container with a total volume of 5.oo L
Alla [95]

Answer:

1 atm

Explanation:

Step 1: Write the balanced equation

NH₄OH(aq) ⇒ H₂O(l) + NH₃(g)

Step 2: Calculate the moles corresponding to 8 g of NH₄OH

The molar mass of NH₄OH is 35.04 g/mol.

8 g × 1 mol/35.04 g = 0.2 mol

Step 3: Calculate the moles of NH₃ formed from 0.2 moles of NH₄OH

The molar ratio of NH₄OH to NH₃ is 1:1. The moles of NH₃ formed are 1/1 × 0.2 mol = 0.2 mol

Step 4: Calculate the pressure of 0.2 moles of NH₃ in a container of 5.00 L at 25 °C (298 K)

We will use the ideal gas equation.

P × V = n × R × T

P = n × R × T / V

P = 0.2 mol × 0.0821 atm.L/mol.K × 298 K / 5.00 L

P = 1 atm

7 0
3 years ago
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