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umka2103 [35]
3 years ago
10

What is the concentration of NaCI in an aqueous solution that contains 0.032 grams of NaCI in 600. Grams of the solution

Chemistry
1 answer:
jolli1 [7]3 years ago
8 0

Answer:

0.00032 Grams of NaCl per 1 gram of the solution

Explanation:

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Why does argon exist in nature as individual argon atoms and chlorine exist in nature as 2 chlorine atoms covalently bonded toge
Katarina [22]

Answer:

Argon has 8 valence electrons and no extras, it does not require a bond in order to fill its shells, its satisfied by itself.

Chlorine is missing 1 Electron, if it connects with another Chlorine it will be satisfying both of their needs with a Covalent bond.

Explanation:

8 0
3 years ago
What element has greatest atomic radius from group 3?
stira [4]

Answer:

i think iron

Explanation:

i not sure with my ans

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3 years ago
To grow or reach the next stage in a life cycle is to develop.
gogolik [260]

Answer:

It's obviously true

Explanation:

As we have evolved over the years we have become more advanced

5 0
3 years ago
When 33 g of CaO and 10 g of H2O react, how many grams of calcium hydroxide would you expect to be produced* Explain your answer
MrMuchimi

Answer:

41.44 g

Explanation:

First of all, we must put down the equation of the reaction;

CaO + H2O ----->Ca(OH)2

Number of moles of CaO = 33g/56 g/mol = 0.59 moles

Number of moles of H20 = 10g/18 g/mol = 0.56 moles

Since the reaction is in 1:1 mole ration, H2O is the limiting reactant

Hence;

mass of Ca(OH)2 produced = 0.56 moles * 74 g/mol = 41.44 g

7 0
3 years ago
Read 2 more answers
Calculate the moles of of Fe that would be needed to form 336 grams of Cl2 (round your answer to 2 decimals)
IrinaVladis [17]

Answer:

6.32 moles of Fe

Explanation:

The given chemical equation is presented as follows;

2Fe + 3Cl₂ → 2FeCl₃

The mass of Cl₂ in the reaction = 336 grams

The molar mass of chlorine gas Cl₂ = 35.435 g/mol

The number of moles, n = Mass/(Molar mass)

The number of moles of Cl₂ in the reaction, n = 336 g/(35.435 g/mol) ≈ 9.842 moles

From the given reaction, 3 moles of Cl₂ react with 2 moles of Fe to produce 2 moles of FeCl₃

By the law of definite proportions, we have that 9.482 moles of Cl₂ will react with approximately 9.482 × 2/3 = 6.32 moles of Fe to produce approximately 6.32 moles of FeCl₃

Therefore, approximately 6.32 moles of Fe will be required to react with 336 grams of Cl₂.

8 0
2 years ago
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