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Firdavs [7]
3 years ago
9

Find the solution set. y^2+4y=0 seperate the two values with a comma

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
6 0

Answer:

y = - 4, y = 0

Step-by-step explanation:

Given

y² + 4y = 0 ← factor out y from each term on the left side

y(y + 4) = 0 ← in factored form

Equate each factor to zero and solve for y

y = 0

y + 4 = 0 ⇒ y = - 4

zvonat [6]3 years ago
3 0

Answer:

y=0,y=-4

Step-by-step explanation:

y^2+4y=0

In this kind of question,you will have to look for what is common to the two figures

Then solve,it was observed that y is common to the two,then you will have to factorise

y(y+4)=0

Which means that y outside the bracket equals to 0

That is y=0

Let's move to the bracket

y+4=0

Substrate 4 from both sides y=-4

We were able to get to values for y

y=0,y=-4

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. Suppose the coordinate of A is 0 and AR = 5 and AT = 7.
ASHA 777 [7]
<h3>Possible coordinates of R = -5 or 5</h3><h3>Possible coordinates of T = -7 or 7</h3>

==================================================

Explanation:

If we're on a number line, then R could be at either R = 5 or R = -5. This is so the distance from A to R is 5 units. Distance is never negative. You count out the spaces to get the distance, or use subtraction and absolute value.

Saying "distance from A to R is 5" can be written as AR = 5. Meaning segment AR is 5 units long.

Now if AT = 7, then T could be at 7 or -7 on the number line. The reasoning as similar as to why R could be at -5 or 5.

8 0
4 years ago
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro
Vinvika [58]

Answer:

40.1% probability that he will miss at least one of them

Step-by-step explanation:

For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

0.95 probaiblity of hitting a target

This means that p = 0.95

10 targets

This means that n = 10

What is the probability that he will miss at least one of them?

Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So

P(X = 10) + P(X < 10) = 1

We want P(X < 10). So

P(X < 10) = 1 - P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{10,10}.(0.95)^{10}.(0.05)^{0} = 0.5987

P(X < 10) = 1 - P(X = 10) = 1 - 0.5987 = 0.401

40.1% probability that he will miss at least one of them

7 0
3 years ago
XY bisects AB a point G. Which of the following is true about G?
tekilochka [14]
I'm thinking C because if it bisects it, it divides it which means it's it midpoint.
5 0
4 years ago
Read 2 more answers
In the first quadrant you start at (7,3) and move 5 unit left
AveGali [126]

Answer:

That would be (2,3)

Step-by-step explanation:

When we're moving left in the coordinate plane, we are subtracting the x-coordinate by how much distance we move.

In this case, 7-5=2, so the new x-coordinate is 2, but the y-coordinate doesn't change since we're going horizontally and not vertically.

7 0
3 years ago
Which pair of angles are corresponding angles?
miv72 [106K]
2 and 6 are corresponding
3 0
3 years ago
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