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Mice21 [21]
3 years ago
14

If x is an integer, what is the least possible value of x for a rectangular lot

Mathematics
1 answer:
AlexFokin [52]3 years ago
7 0

Answer:

k = 13The smallest zero or root is x = -10

===============================

note: you can write "x^2" to mean "x squared"

f(x) = x^2+3x-10

f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5

f(x+5) = (x^2+10x+25)+3(x+5)-10

f(x+5) = x^2+10x+25+3x+15-10

f(x+5) = x^2+13x+30

Compare this with x^2+kx+30 and we see that k = 13

x^2+13x+30 = 0

(x+10)(x+3) = 0

x+10 = 0 or x+3 = 0

x = -10 or x = -3

The smallest zero is x = -10 as its the left-most value on a number line.

Step-by-step explanation: Hope this helps kind of.

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Answer:

the decimal measuring system based on the meter, liter, and gram as units of length, capacity, and weight or mass. The system was first proposed by the French astronomer and mathematician Gabriel Mouton (1618–94) in 1670 and was standardized in France under the Republican government in the 1790s.

Step-by-step explanation:

7 0
3 years ago
2+2+3+6+8-5+0+9-8+4=​
ryzh [129]

Answer:

2+2=4+3=7+6=13+8=16+5=21+9=30-8=22+4=26

7 0
3 years ago
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Find the value of x (round to the nearest tenths)<br> 3x<br> 4x
Schach [20]

Answer:

Sorry nakalimutan ko

Step-by-step explanation:

Di koma search

5 0
2 years ago
Can someone explain to me the steps how they got 2 √4^2+2x-3-2 from this question…
Naddik [55]

Step-by-step explanation:

with your square root symbol I never know what is inside the square root and what is possibly outside.

so, I can only guess and see what comes close.

f(x) = 2x² + x - 1

g(x) = sqrt(2x - 1) ??? is that so ?

h(x) = -2

2g(f(x)) + h(x)

g(f(x)) means that the whole f(x) expression is used as x in g(x).

the whole combined function is then

2×sqrt(2(2x² + x - 1) - 1) - 2

2×sqrt(4x² + 2x - 2 - 1) - 2

2×sqrt(4x² + 2x - 3) - 2

and if I am not mistaken, then this is the solution you mentioned at the beginning (if I try to read between the typos and missing info).

this is how people get to this.

do you understand it now ? or is there still something unclear ?

6 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%2F7%7D%7B7%5Csqrt%7B10%7D%2F2%20%7D" id="TexFormula1" title="\frac{3/7}{7\sqrt{10}
VashaNatasha [74]

Multiply the numerator and denominator by 7×2 = 14 to eliminate the denominators of those fractions:

\dfrac{\dfrac37}{\dfrac{7\sqrt{10}}2}\times\dfrac{14}{14}=\dfrac{3\times2}{7\sqrt{10}\times7}=\dfrac6{49\sqrt{10}}

Rationalize the denominator by multiplying both numerator and denominator by √10:

\dfrac6{49\sqrt{10}}\times\dfrac{\sqrt{10}}{\sqrt{10}}=\dfrac{6\sqrt{10}}{49(\sqrt{10})^2}=\dfrac{6\sqrt{10}}{49\times10}=\dfrac{6\sqrt{10}}{490}

Lastly, cancel the common factor of 2 in both the numerator and denominator (which comes from 6 = 2×3 and 490 = 2×245):

\dfrac{6\sqrt{10}}{490}=\dfrac{3\sqrt{10}}{245}}

8 0
3 years ago
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