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3 years ago

If x is an integer, what is the least possible value of x for a rectangular lot

Mathematics

1 answer:

AlexFokin [52]3 years ago

7 0

Answer:

k = 13The smallest zero or root is x = -10

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note: you can write "x^2" to mean "x squared"

f(x) = x^2+3x-10

f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5

f(x+5) = (x^2+10x+25)+3(x+5)-10

f(x+5) = x^2+10x+25+3x+15-10

f(x+5) = x^2+13x+30

Compare this with x^2+kx+30 and we see that k = 13

x^2+13x+30 = 0

(x+10)(x+3) = 0

x+10 = 0 or x+3 = 0

x = -10 or x = -3

The smallest zero is x = -10 as its the left-most value on a number line.

Step-by-step explanation: Hope this helps kind of.

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How to write 1000= in Exponential form

Nadusha1986 [10]

Answer:

10x^{3}[/tex]

Step-by-step explanation:

$10x^{3}$

=10·10·10

=1000

5 0

3 years ago

Read 2 more answers

Noa hopes to pick the winning ticket during her math class’s raffle. the student who picks the ticket with a true statement will

Natali5045456 [20]

Answer: The winning ticket is $2(x-6)=-35$ is equivalent to $2x=-23$ .

Step-by-step explanation:

Let's check all the options

$4(x-5)=35$ is not equivalent to $4x=40$

$\text{since }4(x-5)=35\\\Rightarrow4x-20=35\\\Rightarrow4x=35+20\\\Rightarrow4x=55$

$8(x-7)=35$ is not equivalent to $8x=28$

$\text{since }8(x-7)=35\\\Rightarrow8x-56=35\\\Rightarrow8x=35+56\\\Rightarrow8x=91$

$2(x-6)=-35$ is equivalent to $2x=-23$

$\text{since }2(x-6)=-35\\\Rightarrow2x-12=-35\\\Rightarrow2x=-35+12\\\Rightarrow2x=-23$

$9(x-6)=-35$ is not equivalent to $9x=-29$

$\text{since }9(x-5)=-35\\\Rightarrow9x--40=-35\\\Rightarrow9x=-35+40\\\Rightarrow9x=5$

Thus, the winning ticket is $2(x-6)=-35$ is equivalent to $2x=-23$ .

4 0

3 years ago

Read 2 more answers

Vertical angle of isoceles triangle is 50° while it's base angles are together 2x .find x

Ghella [55]

Answer:

The sum of all the angles of an isoceles triangle is 180°

So it's 50° + 2x° = 180°

50 + 2x = 180

2x = 180 - 50

2x = 130

x = 130/2

x = 65

7 0

3 years ago

Traveling math word problem - thank you! :)

Anni [7]

We are given:

car and train leave at the same time

average velocity of car = 50 miles/hour

average velocity of train = 70 miles/hour

train arrives 2 hours early

Assuming variables and making equations!

let the time taken by the train = t hours

since the car arrived late, it took more time as compared to the train

time taken by the car = t + 2 hours

since the distance from Pasadena to Sacramento doesn't change, both the vehicles covered the same distance, d

Distance travelled by the car:

d = 50 $\frac{miles}{hour}$ * (t+2) hours [distance = velocity * time]

d = 50(t+2) miles

rewriting in terms of t

$t = \frac{d-100}{50}$

Distance travelled by the train:

d = 70 $\frac{miles}{hour}$ * t hours

d = 70t miles

rewriting in terms of t

$t = \frac{d}{70}$

now we have two expressions for t, both of which are equal because t is just the time taken by the train

Finding the distance:

$t = \frac{d-100}{50}$

$t = \frac{d}{70}$

because t is the same:

$\frac{d-100}{50} = \frac{d}{70}$

$\frac{d-100}{5} = \frac{d}{7}$

7(d - 100) = 5(d)

7d - 700 = 5d

(7d - 5d) - 700 = 0 [subtracting 5d from both sides]

2d = 700 [adding 700 on both sides]

d = 350 miles [dividing both sides by 2]

The distance between Pasadena and Sacramento is 350 miles!

7 0

2 years ago

Preserve What is this 3 digit number

Pie

100 I don’t really know

8 0

3 years ago