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aleksandrvk [35]
3 years ago
13

How many atoms are in 13.0 g Sr

Chemistry
1 answer:
Mkey [24]3 years ago
6 0

Answer: 7.505

×

10

22

atoms. (rounded to third place of decimal)

Explanation:

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A student finds that 4700 J of heat are required to raise the temperature of 250.0 g of metal X from 22°C to 63°C. Based on the
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Explanation:

the answer and explanation is in the picture

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When oxygen reacts with hydrogen, it has the capacity to release 29 kilojoules of energy. Inside a fuel cell, oxygen reacts with
Vanyuwa [196]

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79

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Calculate the amount of heat required for the evaporation of 105.0 g of water at 100.0 c
son4ous [18]
To determine the amount of heat needed to evaporate a certain amount of water at its boiling point, we use the equation,

                  H = m(Hv)

where H is the heat, m is the mass (in grams), and Hv is the latent heat of vaporization. Substituting the known values,

                 H = (105 g)(540 cal/g)

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Answer: 56.7 kcal
8 0
4 years ago
Ionic bonds form between which two types of elements?​
Alla [95]

Answer:

Ionic bonds usually occur between metal and nonmetal ions. For example, sodium (Na), a metal, and chloride (Cl), a nonmetal, form an ionic bond to make NaCl.

Explanation:

4 0
3 years ago
Read 2 more answers
If the volume of oxygen gas is 259 cm3 at 112 kPa, what would the volume be at 101.3 kPa?
NARA [144]

Answer:

<h3>The answer is 286.36 cm³</h3>

Explanation:

In order to find the volume be at 101.3 kPa we use Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question

P1 = 112 kPa = 112000 Pa

V1 = 259 cm³

P2 = 101.3 kPa = 101300 Pa

We have

V_2 =  \frac{112000 \times 259}{101300}  =  \frac{29008000}{101300}  \\  = 286.3573543...

We have the final answer as

<h3>286.36 cm³</h3>

Hope this helps you

6 0
3 years ago
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