<u>Answer:</u> The concentration of nitrogen dioxide at equilibrium is 0.063 M
<u>Explanation:</u>
We are given:
Initial concentration of nitrogen dioxide = 0.0250 M
Initial concentration of dinitrogen tetraoxide = 0.0250 M
For the given chemical equation:

<u>Initial:</u> 0.025 0.025
<u>At eqllm:</u> 0.025-x 0.025+2x
The expression of
for above equation follows:
![K_c=\frac{[NO_2]^2}{[N_2O_4]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BNO_2%5D%5E2%7D%7B%5BN_2O_4%5D%7D)
We are given:

Putting values in above expression, we get:

Neglecting the negative value of 'x', because concentration cannot be negative
So, equilibrium concentration of nitrogen dioxide = (0.025 + 2x) = [0.025 + 2(0.019)] = 0.063 M
Hence, the concentration of nitrogen dioxide at equilibrium is 0.063 M
Chemical or molecular formulas? Symbols from the periodic table are used to show which atoms are present in a molecule and subscripts show the number of atoms and of each type in the molecule.
Answer:
TIMED HELP ASAP
19.11 g of MgSO₄ is placed into 100.0 mL of water. The water's temperature increases by 6.70°C. Calculate ∆H, in kJ/mol, for the dissolution of MgSO₄. (The specific heat of water is 4.184 J/g・°C and the density of the water is 1.00 g/mL). You can assume that the specific heat of the solution is the same as that of water.
Answer:
M=3
B=25
Equation= 3x+25
Explanation:
M is your slope and if you follow the slope- intercept formula (y=m+b) you just need to plug in the numbers.
Thus your answer:
M=3
B=25
Equation= 3x+25