16 g. The mass of 0.60 mol Al is 16 g.
Molar mass of Al = 26.98 g/mol
Mass of Al = 0.60 mol Al x (26.98 g Al/1 mol Al) = 16 g Al
Answer:
Explanation:
The answer is C Enthaply and entropy because temperature plays a big role in reactions
I am not positive this is what you want but here lol:
The Earth's surface is about 71 percent water spreading over many oceans, rivers, and lakes. This also includes the droplets of water on the morning grass, the undrained water from the rain, puddles that never evaporated, etc. As this water is heated up by the Sun, its' molecules start to move faster as it turns into gas and evaporates. As it evaporates it rises, however, the cooler temperatures in the high altitude of Earth's atmosphere make it condense into large clouds. When so much water has evaporated and the cloud very dense, gravity brings down the water from the clouds onto the ground in the form of rain. This completes the water cycle as the water will either turn into runoff, stay on the surface of the Earth, or seep into the ground. Then the water evaporates again, and the whole process starts over.
*Hope this helped!! Have a good night/ day wherever you are! : )*
Answer:
140. J/g*K
Explanation:
To find the specific heat capacity, you need to use the following equation:
Q = mcΔT
In this equation,
-----> Q = energy/heat (J)
-----> m = mass (g)
-----> c = specific heat (J/mole*K)
-----> ΔT = change in temperature (K)
Before you can use the equation above, you need to (1) convert kg to grams, then (2) convert grams to moles (via molar mass), and then (3) convert Celsius to Kelvin. The final answer should have 3 significant figures.
1.11 kg C₄H₈O₂ x 1,000 = 1110 g
Molar Mass (C₄H₈O₂): 4(12.01 g/mol) + 8(1.008 g/mol) + 2(16.00 g/mol)
Molar Mass (C₄H₈O₂): 88.104 g/mol
1110 grams C₄H₈O₂ 1 mole
------------------------------ x ------------------------- = 12.6 moles C₄H₈O₂
88.104 grams
34.5 °C + 273 = 307.5 K
52.3 °C + 273 = 325.3 K
Q = mcΔT <----- Equation
3.14 x 10⁴ J = (12.6 moles)c(325.3 K - 307.5 K) <----- Insert values
3.14 x 10⁴ J = (12.6 moles)c(17.8) <----- Subtract
3.14 x 10⁴ J = (224.28)c <----- Multiply 12.6 and 17.8
140. = c <----- Divide both sides by 224.28
**this answer may be slightly off due to using different molar masses/Kelvin conversions**
