As per Newton's law of inertia we can say every object will move in its state of motion either in the state of rest or will move with same constant velocity until some unbalanced external force will act upon it
so here we have to fill the space which says that stationary object can start or moving object will change its direction only in which case
so here the correct answer should be Unbalanced Force condition we will obtain such situation.
so we have
<u>Unbalance force</u> can cause a stationary object to start moving or a moving object to change its speed or direction or both.
Answer:
The temperature would fall.
Explanation:
The question can be solved by using first law of thermodynamics.
The law states:
The change in internal energy of the system is equal to the heat energy supplied to the system minus the workdone by the system.
ΔU = Q - W
where ΔU is change in internal energy of the system
Q is energy given to the system
W is workdone by the system
Because the charges are repelling each other it means they will move away from each other and their repulsive forces will do positive workdone (workdone is defined as distance moved in the direction of the force applied). Therefore W > 0.
There is no energy supplied to the system so Q = 0.
Using the relation ΔU = Q - W we can see that if Q = 0 and W > 0 then ΔU < 0. Hence internal energy of the system falls so the temperature falls.
Downward movement under the force of gravity only.
Material, eg copper, has lower resistance than steel. length - longer wires have greater resistance. thickness - smaller diameter wires have greater resistance. temperature - heating a wire increases its resistance.
Answer:
image is vertical at distance -203.62 cm
magnification is 2.110
Explanation:
given data
n = 1.51
distance u = 96.5 cm
concave radius r1 = 24 cm
convex radius r2 = 19.1 cm
to find out
final image distance and magnification
solution
we will apply here lens formula to find focal length f
1/f = n-1 ( 1/r1 - 1/r2) .......................1
put here all value
1/f = 1.51 -1 ( -1/24 + 1/19.1)
f = 183.43
so from lens formula
1/f = 1/v + 1/u .............................2
put here all value and find v
1/183.43 = 1/v + 1/96.5
so
v = −203.62 cm
so here image is vertical at distance -203.62 cm
and
magnification are = -v /u
magnification = 203.62 / 96.5
magnification is 2.110