Answer:
La fuerza magnética del electrón es 6.41x10⁻¹³ N.
Explanation:
Podemos encontrar la fuerza magnética (F) usando la ley de Lorentz:
![F = qv\times B](https://tex.z-dn.net/?f=%20F%20%3D%20qv%5Ctimes%20B%20)
En donde:
q: es la carga del electrón = 1.602x10⁻¹⁹ C
v: es la velocidad del electrón = 5x10⁶ m/s
B: es el campo magnético = 0.8 T
Por lo tanto, la fuerza magnética del electrón es 6.41x10⁻¹³ N.
Espero que te sea de utilidad!
Answer:
The minimum frequency of the coil is 7.1 Hz
Explanation:
Given;
number of turns, N = 200 turns
cross sectional area, A = 300 cm² = 300 x 10⁻⁴ m²
magnitude of magnetic field strength, B = 30 x 10⁻³ T
maximum value of the induced emf, E = 8 V
Maximum induced emf is given as;
E = NBAω
where
ω is angular velocity (ω = 2πf)
E = NBA2πf
where;
f is the minimum frequency, measured in hertz (Hz)
f = E / (NBA2π)
f = 8 / (200 x 30 x 10⁻³ x 300 x 10⁻⁴ x 2 x 3.142)
f = 7.073 Hz
f = 7.1 Hz
Therefore, the minimum frequency of the coil is 7.1 Hz
Answer:
This question is asking to identify the following variables:
Independent variable (IV): Battery
Dependent variable (DV): Time the clock stopped
Constant: Same clock
Control: No stated control
Explanation:
The independent variable in an experiment is the variable that is subject to manipulation or change by the experimenter. In this experiment, the independent variable is the BATTERIES (Duracell, Energizer, Kroger brand, EverReady).
The dependent variable is the variable that responds to the changes made to the independent variable. It is the variable that the experimenter measures. In this case, the dependent variable is the TIME IT TAKES FOR THE CLOCK TO STOP.
Constants or control variable is the variable that the experimenter keeps constant or unchanged for all groups throughout the experiment in order not to influence the outcome of the experiment. The constant in this case is the SAME CLOCK USED.
Control group is the group that does not receive the experimental treatment or independent variable in an experiment. In this case, all groups received a different kind of battery.
Every piece of matter begins “Out of this world”
Answer:
KE = 1.75 J
Explanation:
given,
mass of ball, m₁ = 300 g = 0.3 Kg
mass of ball 2, m₂ = 600 g = 0.6 Kg
length of the rod = 40 cm = 0.4 m
Angular speed = 100 rpm= ![100\times \dfrac{2\pi}{60}](https://tex.z-dn.net/?f=%20100%5Ctimes%20%5Cdfrac%7B2%5Cpi%7D%7B60%7D)
=10.47\ rad/s
now, finding the position of center of mass of the system
r₁ + r₂ = 0.4 m.....(1)
equating momentum about center of mass
m₁r₁ = m₂ r₂
0.3 x r₁ = 0.6 r₂
r₁ = 2 r₂
Putting value in equation 1
2 r₂ + r₂ = 0.4
r₂ = 0.4/3
r₁ = 0.8/3
now, calculation of rotational energy
![KE = \dfrac{1}{2}I_1\omega^2+\dfrac{1}{2}I_2\omega^2](https://tex.z-dn.net/?f=KE%20%3D%20%5Cdfrac%7B1%7D%7B2%7DI_1%5Comega%5E2%2B%5Cdfrac%7B1%7D%7B2%7DI_2%5Comega%5E2)
![KE = \dfrac{1}{2}\omega^2 (I_1 +I_2)](https://tex.z-dn.net/?f=KE%20%3D%20%5Cdfrac%7B1%7D%7B2%7D%5Comega%5E2%20%28I_1%20%2BI_2%29)
![KE = \dfrac{1}{2}\omega^2 (m_1r_1^2 +m_2r^2_2)](https://tex.z-dn.net/?f=KE%20%3D%20%5Cdfrac%7B1%7D%7B2%7D%5Comega%5E2%20%28m_1r_1%5E2%20%2Bm_2r%5E2_2%29)
![KE = \dfrac{1}{2}\times 10.47^2(0.3\times (0.8/3)^2 +0.6\times (0.4/3)^2)](https://tex.z-dn.net/?f=KE%20%3D%20%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%2010.47%5E2%280.3%5Ctimes%20%280.8%2F3%29%5E2%20%2B0.6%5Ctimes%20%280.4%2F3%29%5E2%29)
KE = 1.75 J
the rotational kinetic energy is equal to 1.75 J