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Vsevolod [243]
3 years ago
9

What are factor affecting resistance?​

Physics
1 answer:
Keith_Richards [23]3 years ago
4 0
Material, eg copper, has lower resistance than steel. length - longer wires have greater resistance. thickness - smaller diameter wires have greater resistance. temperature - heating a wire increases its resistance.
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If y = 0.02 sin (30x – 200t) (SI units), the frequency of the wave is
leva [86]

Answer:

31.831 Hz.

Explanation:

<u>Given:</u>

  • \rm y = 0.02\sin(30x-200 t).

The vertical displacement of a wave is given in generalized form as

\rm y = A\sin(kx -\omega t).

<em>where</em>,

  • A = amplitude of the displacement of the wave.
  • k = wave number of the wave = \dfrac{2\pi }{\lambda}.
  • \lambda = wavelength of the wave.
  • x = horizontal displacement of the wave.
  • \omega = angular frequency of the wave = \rm 2\pi f.
  • f = frequency of the wave.
  • t = time at which the displacement is calculated.

On comparing the generalized equation with the given equation of the displacement of the wave, we get,

\rm A=0.02.\\k=30.\\\omega =200.\\

therefore,

\rm 2\pi f=200\\\\\Rightarrow f = \dfrac{200}{2\pi}=31.831\ Hz.

It is the required frequency of the wave.

3 0
3 years ago
Series circuits are characterized by the fact that there is a single pathway by which charge can travel. True or false?
Ulleksa [173]
I Think Its True My  Dude Or Dudette
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Hope this helps
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Zane
6 0
3 years ago
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Suppose that you are standing on a train accelerating at 0.20g. What minimum coefficient of static friction must exist between y
Ilia_Sergeevich [38]
Acceleration = (0.2 x g) = 1.96m/sec^2. 
<span>Accelerating force on 1kg. = (ma) = 1.96N. </span>
<span>1kg. has a weight (normal force) of 9.8N. </span>
<span>Coefficient µ = 1.96/9.8 = 0.2 minimum. </span>

<span>Coefficient is a ratio, so holds true for any value of mass to find accelerating force acting. </span>
<span>e.g. 75kg = (75 x g) = 735N. </span>
<span>Accelerating force = (735 x 0.2) = 147N</span>
5 0
4 years ago
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The average power of a wind turbine is 3 MW.
IgorC [24]

Answer:

a

Explanation:

5 0
3 years ago
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It requires a force of 100 N to stretch a spring of negligible mass by a distance of 0.1 m. If the spring instead stretches a di
Mariana [72]

by the formula of spring force we know that

F = kx

here we know that

F = 100 N

x = 0.1 m

now we will have

100 = k \times 0.1

k = 1000 N/m

now by similar way if the stretch in spring is 0.25 m

force is given by

F = kx

F = 1000 \times 0.25

F = 250 N

so it will require F = 250 N force

5 0
3 years ago
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