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algol13
3 years ago
9

What is the approximate radius of pluto

Physics
2 answers:
krek1111 [17]3 years ago
3 0
1200 km to 2 s.f.

If you want to approximate it further then 1000 km.
Taya2010 [7]3 years ago
3 0
783.4 is the radius of pluto
 0.01303, 5.9724, 0.0022. Volume (1010<span> km</span>3<span>), 0.697, 108.321, 0.0064. Equatorial </span>radius<span> (km),</span>
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A 1.50 cm high diamond ring is placed 20.0 cm from a concave mirror with radius of curvature 30.00 cm. The magnification is ____
Rama09 [41]

Answer:

Magnification, m = -0.42

Explanation:

It is given that,

Height of diamond ring, h = 1.5 cm

Object distance, u = -20 cm

Radius of curvature of concave mirror, R = 30 cm

Focal length of mirror, f = R/2 = -15 cm (focal length is negative for concave mirror)

Using mirror's formula :

\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}, f = focal length of the mirror

\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}

\dfrac{1}{v}=\dfrac{1}{-15}+\dfrac{1}{-20}

v = -8.57 cm

The magnification of a mirror is given by,

m=\dfrac{-v}{u}

m=\dfrac{-(-8.57)}{-20}

m = -0.42

So, the magnification of the concave mirror is 0.42. Thew negative sign shows that the image is inverted.

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4 years ago
All planets have magnetic fields. <br> T or F
ra1l [238]

Answer:

No, not all planets have magnetic fields.

Explanation:

8 0
3 years ago
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What is the coefficient for titanium tetrachloride when the equation below is balanced?
Alexus [3.1K]

the coefficient of TiCl4 would be 1

3 0
3 years ago
A 540 kg satellite moves through deep space with a speed of 27 m/s. A booster rocket on the satellite fires for 1.4 s, giving a
prohojiy [21]

Answer: a

Explanation: because the answer is 1.4444444 and that's the closest

6 0
3 years ago
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Two trains move towards each other on a straight track/railroad. The left train has a constant speed of 29ms, the right train ha
laiz [17]

Answer:

The left train travels 2378 m until it reaches the meeting point.

Explanation:

The equation for the position of the trains is the following:

x = x0 + v · t

Where:

x = position at time t

x0 = initial position

v = velocity

t = time

If we place the origin of the frame of reference at the initial position of the left train, the right train will be at an initial position of 4744. 6 m relative to the left train. The velocity of the right train will be negative because it will be heading towards the origin.

At the meeting point, the position of both trains is the same:

x left train = x right train

x0₁ + v₁  ·t = x0₂ + v₂ · t

0m + 29 m/s · t = 4744.6 m - 29 m/s · t

58 m/s · t = 4744.6 m

t = 4744.6 m / 58 /s

t = 82 s

The position of the left train at that time will be:

x = x0 + v · t

x = 0 m + 29 m/s · 82 s

x = 2378 m

The left train travels 2378 m until it reaches the meeting point.

7 0
3 years ago
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