Question

What is the temperature of 0.45 moles of Neon gas at 1920 mm Hg if it occupies 22,400 ml of volume?

Answer 1

Answer:

The temperature is 1,532.52 °K= 1,252.37 °C

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The equation known as the ideal gas equation explains the relationship between the four variables P (Pressure), V (Volume), T (Temperature) and n (Amount of substance) and where R is the molar constant of the gases as follows :

P * V = n * R * T

In this case:

• P= 1920 mmHg
• V= 22,400 mL= 22.4 L (Being 1 L=1,000 mL)
• n= 0.45 moles

• R= 62.36367 $\frac{mmHg*L}{mol*K}$

• T=?

Replacing:

1920 mmHg* 22.4 L= 0.45 moles* 62.36367 $\frac{mmHg*L}{mol*K}$*T

Solving:

$T=\frac{1920 mmHg* 22.4 L}{0.45 moles* 62.36367\frac{mmHg*L}{mol*K}}$

T=1,532.52 °K= 1,252.37 °C (Being 0°C=273.15°K)

The temperature is 1,532.52 °K= 1,252.37 °C