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3 years ago

PLEASE HELP ME!!!

Mathematics

2 answers:

Brums [2.3K]3 years ago

8 0

Answer:

$\frac{13+\sqrt{29}}{10} , \frac{13-\sqrt{29}}{10}$

Step-by-step explanation:

$5x^2-13x+7=0$

$x=\dfrac{13\pm \sqrt{169-140}}{10}=\frac{13+\sqrt{29}}{10} , \frac{13-\sqrt{29}}{10}$ . Hope this helps!

UNO [17]3 years ago

8 0

Answer:

$\frac{13+\sqrt{29}}{10} , \frac{13-\sqrt{29}}{10}$

Step-by-step explanation:

Verified correct with K12 test.

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Find the coordinates of the midpoint of a segment with the given endpoints. A(-12,2), C(-3,5)

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The coordinates of the midpoint of a segment with the given endpoints will be (-7.5, 3.5).

<h3>What is the mid-point of the line segment?</h3>

Let AB be the line segment and C be the mid-point of line segment AB. Let the coordinate of point A (x₁, y₁), the coordinate of point B (x₂, y₂), and the coordinate of the mid-point (x, y).

Then the coordinate of the mid-point of the line segment is given as,

(x, y) = [(x₁ + x₂) / 2, (y₁ + y₂) / 2]

The endpoints are A(-12, 2) and C(-3,5).

Then the coordinates of the midpoint of a segment with the given endpoints will be

(x, y) = [(- 12 - 3) / 2, (2 + 5) / 2]

(x, y) = (-15/2, 7/2)

(x, y) = (-7.5, 3.5)

The coordinates of the midpoint of a segment with the given endpoints will be (-7.5, 3.5).

More about the mid-point of the line segment link is given below.

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1 year ago

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What is the slope of the line passing through (1, 2) and (3, 8)? A: slope = 1/7 B: slope = 1/3 C: slope = 3 D: slope = 7

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Slope = (y2-y1)/(x2-x1) = (8-2)/(3-1) = 6/2 = 3. So the answer is c.

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What is the slope of a line that is perpendicular to the graph of y = –3x?

Morgarella [4.7K]

Step-by-step explanation:

Hey there!

The equation is; y= -3x

or, 3x+y = 0.......... (I)

From equation (I)

$slope(m1) = \frac{ - coeff. \: of \: x}{coeff. \: of \: y}$

$m1= \frac{ - 3}{1}$

Therefore, m= -3

Now, As per the condition of perpendicular lines;

M1*M2 = -1

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M2= -1/-3

Therefore, the slope of a line which is perpendicular to the equation is; 1/3.

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