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DochEvi [55]
3 years ago
13

See if you can help thank you!!

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
4 0

C

the square of the sum of 7 times x and 3 is expressed as

7x + 3 ← the sum of 7 times x and 3

(7x + 3)² ← the square of the sum of 7 times x and 3

4 times the difference of x and 1 is expressed as

x- 1 ← the difference of x and 1

4(x - 1) ← 4 times the difference of x and 1

putting it all together gives

(7x + 3 )² / 4(x - 1 ) → C


Troyanec [42]3 years ago
4 0

The way to read math problems is to read and do little parts at a time. Don't try and understand it all at once. That's what you try and do when you are reading a novel or a persuasive essay. Do things as you would when you are trying to parse a sentence.

The numerator is determined by the language before the word divide. What does it say? Concentrate on everything after square.

sum of 7 times x  plus 3. That translates into 7x + 3

Now go look at the word square. It means that you square 7x + 3

Numerator: (7x + 3)^2

Guess what? You have already eliminated B and D. So you are left with A and C.

Denominator: difference between x and 1. Difference means subtract so you have x - 1

Denominator: 4 times the difference between x and 1: 4*(x - 1)

Now put them together.

numerator / denominator

\dfrac{(7x + 3)^2}{(4(x - 1))}

which is C.

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8 0
4 years ago
Use the distance formula to determine the distance between (-8,10) and (-6,7)
hjlf

Answer:

Distance: \sqrt{13} units

Step-by-step explanation:

The distance formula is d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} where:

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  • (x_1,y_1) are the coordinates of the first point
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We are given that:

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  • (x_2,y_2)=(-6,7)

To determine the value of our distance, d, we plug in our given information into the formula and solve for

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

d=\sqrt{(-6-(-8))^2+(7-10)^2}

d=\sqrt{(-6+8)^2+(-3)^2}

d=\sqrt{(2)^2+(-3)^2}

d=\sqrt{4+9}

d=\sqrt{13}

Therefore, the distance between (-8,10) and (-6,7) is \sqrt{13} units.

See the attached graph for a visual.

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