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bonufazy [111]
3 years ago
11

Giving brainliest for CORRECT awnser.

Mathematics
1 answer:
Doss [256]3 years ago
8 0

Answer: x - 8

Step-by-step explanation:

Factor it and you'll be fine.

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PLEASE HELP A boat is carrying containers that weigh 1000 pounds each. Use this information to fill in the table. Then plot the
Inessa05 [86]

Answer:

<h2>For the table, the answers are 2000, 4000, 7000. for the graph the plots will be at (2,2000) (4,4000) (7,7000)</h2>

Step-by-step explanation:

A boat is carrying containers that weigh 1000 pounds each.

For the table

2 x 1000 = 2000

4 x 1000 = 4000

7 x 1000 = 7000

For the graph

2, 4, and 7 are given as your X  axis points. You will then raise those answers to your corresponding answers for the table. so your Y axis points will be 2000, 4000, and 7000.

8 0
3 years ago
a city parking garage charges a flat fee of %5.00 for parking, and %1.00 per hour for every hour. (parking for 0 hours is $5, pa
victus00 [196]
Y = x + 5
Just add 5 to the number of hours to get the total cost.
4 0
3 years ago
there are 11 pieces of pie left over in the cafeteria. if 6 pieces are apple and 5 are cherry, what fraction of the remaining pi
Leto [7]

Answer:

\frac{6}{11}

Step-by-step explanation:

we know that

To find what fraction of the remaining pieces are apple, divide the remaining  pieces of apple by the  total remaining pieces

we have that

the remaining  pieces of apple is equal to 6

the  total remaining pieces is 11

so

\frac{6}{11}

8 0
3 years ago
Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose t
andrezito [222]

Answer and Step-by-step explanation: For an exponential distribution, the probability distribution function is:

f(x) = λ.e^{-\lambda.x}

and the cumulative distribution function, which describes the probability distribution of a random variable X, is:

F(x) = 1 - e^{-\lambda.x}

(a) <u>Probability</u> of distance at most <u>100m</u>, with λ = 0.0143:

F(100) = 1 - e^{-0.0143.100}

F(100) = 0.76

<u>Probability</u> of distance at most <u>200</u>:

F(200) = 1 - e^{-0.0143.200}

F(200) = 0.94

<u>Probability</u> of distance between <u>100 and 200</u>:

F(100≤X≤200) = F(200) - F(100)

F(100≤X≤200) = 0.94 - 0.76

F(100≤X≤200) = 0.18

(b) The mean, E(X), of a probability distribution is calculated by:

E(X) = \frac{1}{\lambda}

E(X) = \frac{1}{0.0143}

E(X) = 69.93

The standard deviation is the square root of variance,V(X), which is calculated by:

σ = \sqrt{\frac{1}{\lambda^{2}} }

σ = \sqrt{\frac{1}{0.0143^{2}} }

σ = 69.93

<u>Distance exceeds the mean distance by more than 2σ</u>:

P(X > 69.93+2.69.93) = P(X > 209.79)

P(X > 209.79) = 1 - P(X≤209.79)

P(X > 209.79) = 1 - F(209.79)

P(X > 209.79) = 1 - (1 - e^{-0.0143*209.79})

P(X > 209.79) = 0.0503

(c) Median is a point that divides the value in half. For a probability distribution:

P(X≤m) = 0.5

\int\limits^m_0 f({x}) \, dx = 0.5

\int\limits^m_0 {\lambda.e^{-\lambda.x}} \, dx = 0.5

\lambda.\frac{e^{-\lambda.x}}{-\lambda} = -e^{-\lambda.x} + e^{0}

1 - e^{-\lambda.m} = 0.5

-e^{-\lambda.m} = - 0.5

ln(e^{-0.0143.m}) = ln(0.5)

-0.0143.m = - 0.0693

m = 48.46

6 0
4 years ago
What is the greatest common factor (GCF) of 28 and 70?
cupoosta [38]
14. Fourteen is the answer
8 0
3 years ago
Read 2 more answers
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