Answer:
<em>D.) 0</em>
Step-by-step explanation:
Its not A. cause 2y−2=0 is y = 1
Its not B. cause 2y−1=0 is y = 1/2
Its not C. cause 2y−3=0 is y = 3/2
Soo... The only option left is D.
It IS D. cause 2y − 0 = 0 is y=0
<em>So you are Correct!!!</em>
<em>hope I helped... <3</em>
<em>Good luck dear :)</em>
Answer:
5
Step-by-step explanation:
If X equals 2, then 3 times X would be 6. This is because if a number and a variable are put together, you have to multiply them. 6-1 is 5.
Answer:
a) Var[z] = 1600
D[z] = 40
b) Var[z] = 2304
D[z] = 48
c) Var[z] = 80
D[z] = 8.94
d) Var[z] = 80
D[z] = 8.94
e) Var[z] = 320
D[z] = 17.88
Step-by-step explanation:
In general
V([x+y] = V[x] + V[y] +2Cov[xy]
how in this problem Cov[XY] = 0, then
V[x+y] = V[x] + V[y]
Also we must use this properti of the variance
V[ax+b] =
V[x]
and remember that
standard desviation = ![\sqrt{Var[x]}](https://tex.z-dn.net/?f=%5Csqrt%7BVar%5Bx%5D%7D)
a) z = 35-10x
Var[z] =
Var[x] = 100*16 = 1600
D[z] =
= 40
b) z = 12x -5
Var[z] =
Var[x] = 144*16 = 2304
D[z] =
= 48
c) z = x + y
Var[z] = Var[x+y] = Var[x] + Var[y] = 16 + 64 = 80
D[z] =
= 8.94
d) z = x - y
Var[z] = Var[x-y] = Var[x] + Var[y] = 16 + 64 = 80
D[z] =
= 8.94
e) z = -2x + 2y
Var[z] = 4Var[x] + 4Var[y] = 4*16 + 4*64 = 320
D[z] =
= 17.88
Hi there!

Use the Pythagorean theorem to find the length of the line.
If we draw an imaginary right triangle using the given line as the hypotenuse, we can derive a height of 6 units and a length of 10 units.
Use the Pythagorean theorem equation:
c² = a² + b²
Plug in the height and length:
c² = 6² + 10²
Simplify:
c² = 36 + 100
c² = 136
Take the square root of both sides:
c = √136. The correct answer is D.
The answer is B
seeing there are 3 way to put it
(a+b)(a-b)=a 2-b 2
(a+b)(a-b)=a^2-b^2
(a+b)(a-b)=a2-b2
and option B matches with the second way to put it i hope this helps