(What does this mean?) \"Use a graphing utility\" to graph the equation and find the x- and y-intercepts?

1 answer:

5 0

Base on your question the meaning of that statement that "Use a graphing utility", I think the meaning of the statement is that in getting the graph you must first consider the X and Y coordinates to get the slope of the line and then graph it to the plane and if that happens, you can formulate the equation.

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Use the order pairs to write a function rule. Give the tule in slope-intercept form.

topjm [15]

to get the equation of any straight line, we simply need two points off of it, so hmmm let's use say (-1 , -1.25) and (8 , -3.5)

$(\stackrel{x_1}{-1}~,~\stackrel{y_1}{-1.25})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{-3.5}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-3.5}-\stackrel{y1}{(-1.25)}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{(-1)}}}\implies \cfrac{-3.5+1.25}{8+1}\implies \cfrac{-2.25}{9}\implies -\cfrac{~~ \frac{225}{100}~~}{\frac{9}{1}} \\\\\\ -\cfrac{225}{100}\cdot \cfrac{1}{9}\implies -\cfrac{9}{4}\cdot \cfrac{1}{9}\implies -\cfrac{1}{4}$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1.25)}=\stackrel{m}{-\cfrac{1}{4}}(x-\stackrel{x_1}{(-1)}) \\\\\\ y+1.25=-\cfrac{1}{4}(x+1)\implies y+\cfrac{5}{4}=-\cfrac{1}{4}x-\cfrac{1}{4} \\\\\\ y=-\cfrac{1}{4}x-\cfrac{1}{4}-\cfrac{5}{4}\implies y=-\cfrac{1}{4}x-\cfrac{6}{4}\implies y=-\cfrac{1}{4}x-\cfrac{3}{2}$

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2 years ago

Celik, S. (2011). A media comparison study on first aid instruction. Health Education Journal. 72(1), 95-101

aniked [119]

Answer:

The answer is "Option a".

Step-by-step explanation:

In the given scenario, The appropriate test for the teaching profession's accomplishment pre and post-class would be the two-sample t-test with dependent samples, that's why choice "a" is correct.

7 0

3 years ago

A line passes through the point (-1,-5) and has a slope of -5.

Anna71 [15]

<h3>hello!</h3>

We're given a point that the line intersects and its slope.

Let's use Point-slope:-

$\boxed{y-y1=m(x-x1)}$