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guajiro [1.7K]
3 years ago
12

X and Y together complete a task in 4 days, Y and Z together in 5 days. If they work independently, who will finish the work in

the least time? A. X B. Y C. Z D. Not enough information to decide
Mathematics
1 answer:
pav-90 [236]3 years ago
4 0

Answer:

c, Z

Step-by-step explanation:

x+y=4

<u>y+z=5</u>

y=4-x

4-x+z=5

<u>-</u><u>x</u><u>+</u><u>z</u><u>=</u><u>1</u>

z=1+x

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Does the point (5, 2) satisfy the inequality y &lt; 9x + 4?
Allushta [10]

Answer:

yes

Step-by-step explanation:

2< 9(5) + 4

2 < 45 + 4

2 < 49

6 0
3 years ago
Read 2 more answers
Find x if 2^x=8^3x-8
Anon25 [30]

Step-by-step explanation:

First we have to same the bases.

As we know 8=2^3.

Replace 8 with 2^3.

Like this .

2^3x=2^3(2x+1).

Now 3x=3(2x+1) distribute 3 by the Barker.

3x=6x+3.

6x+3=3x.

6x-3x=-3.

3x=-3.

X=-1.

5 0
2 years ago
Evaluate 5 - t/3 when t = 12.
Nady [450]

5 - t/3

5 - 12 /3

-7/3

4 0
2 years ago
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It is hard to calculate the volume of a mountain but several estimates put the volume of Mount Everest at around 2,413 cubic kil
umka2103 [35]

Answer:

About 609,000 Cowboy stadiums could fit inside of Mount Everest

Step-by-step explanation:

we have

The estimate volume of Mount Everest is at around 2,413\ km^{3}

The Dallas Cowboys Stadium has a volume of 140,000,000\ ft^{3}

step 1

Convert ft³ to km³

we know that

1 km=3,280.84 ft

so

140,000,000\ ft^{3}=140,000,000*(1/3,280.84)^{3}=0.003964\ km^{3}

step 2

To find how many Cowboy stadiums could fit inside of Mount Everest, divide the volume of Mount Everest by the volume of the Dallas Cowboys Stadium

2,413/0.003964=608,729

Round to the nearest Thousands

608,729=609,000

The volume of Mount Everest is about 609,000 times greater than the volume of the Dallas Cowboys Stadium

4 0
2 years ago
Find the missing number so that the equation has no solutions.<br> x+20=<br> –<br> 4x+3
valkas [14]

Answer: Its 3x

Step-by-step explanation:

I don't really know how to explain it.

8 0
3 years ago
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