Answer:
...
Step-by-step explanation:
since they give us the side opposite of the given angle(Opposite) and we are trying to find for a (Adjacent/side), so we use TOA
tan(30)= 
i see u dont want it solved but ill solve it anyways
since a is on the bottom then lets switch them

x= 6.928
Consider the closed region

bounded simultaneously by the paraboloid and plane, jointly denoted

. By the divergence theorem,

And since we have

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have




Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by

, we have

Parameterize

by


which would give a unit normal vector of

. However, the divergence theorem requires that the closed surface

be oriented with outward-pointing normal vectors, which means we should instead use

.
Now,



So, the flux over the paraboloid alone is
Answer:
B
Step-by-step explanation:
You are given two sides and the included angle, so you need to use the law of cosines.
c² = a² + b² - 2ab cos C
c² = 12² + 13² - 2(12)(13)cos 134°
c² = 313 - 312(-0.6947)
c² = 529.733
c = 23.016
Now use the law of sines.
c/sin C = a/sin A
23.016/sin 134° = 12/sin A
sin A = 12 × sin 134° / 23.016
sin A = 0.37504
A = 22.03°
B = 180° - 134° - 22.03°
B = 23.97°
m<A = 22°; m<B = 24°; c = 23 km
Answer: B
Answer:
there was a -12 integer change
Step-by-step explanation:
-22 + 10 = -12