This is the third time and i a really annoyed as i am having my time wasted and points

Mathematics

2 answers:

muminat3 years ago

4 0

Answer: A) 20.9 ; B) 34years

Step-by-step explanation:

Given the following :

AGE (X) - - - - - - - 19 - -20 - - - 21 - - - 22 - - - 23

FREQUENCY (F) - 2 - - 3 - - - - 1 - - - - 4 - - - - 1

MEAN(X) = [AGE(X) × FREQUENCY (F)] ÷ SUM OF FREQUENCY

F*X = [(19 * 2) + (20 * 3) + ( 21 * 1)+(22 * 4)+(23 * 1)]

= 38 + 60 +21 + 88 + 23 = 230

SUM OF FREQUENCY = 2 + 3 + 1 + 4 + 1= 11

MEAN(X) = 230 / 11

X = 20.9

WHEN A NEW PLAYER WAS ADDED :

MEAN (X) = 22

Let age of new player = y

Sum of Ages = 19 + 19 +20 + 20 + 20 + 21 + 22 + 22 + 22 + 22 + 23 + y

Number of players = 11 + 1 = 12

Mean(x) = sum of ages / number of players

New mean (x) = 22

x = (230 + y) / 12

22 = (230 + y) / 12

Cross multiply

264 = 230 + y

y = 264 - 230

y = 34 years

VLD [36.1K]3 years ago

3 0

Answer:

a) 21.0

b) 5yrs

Step-by-step explanation:

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Rzqust [24]

Answer: C is closest to the correct answer

Step-by-step explanation:

Convert the inches into feet (12 inches equal 1 foot). Then convert the mixed fractions into improper fractions and multiply.

$11\ ft\ 2\ in=11\dfrac{2}{12}ft\qquad\longrightarrow \qquad11\dfrac{1}{6}ft\qquad =\qquad \dfrac{67}{6}\ ft\\\\\\9\ ft\ 10\ in= 9\dfrac{10}{12}ft\qquad\longrightarrow \qquad9\dfrac{5}{6}ft\qquad =\qquad \dfrac{59}{6}\ ft\\\\\\\dfrac{67}{6}\ ft\times \dfrac{59}{6}\ ft\times \dfrac{\$2.50}{ft^2}=\dfrac{\$9,882.50}{36}\qquad \longrightarrow \qquad \large\boxed{\$274.51}$