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kumpel [21]
3 years ago
5

Given that a­­b = x, evaluate the following: ab+2

Mathematics
2 answers:
Semmy [17]3 years ago
4 0

Answer:

x+2

Step-by-step explanation:

replace ab with x

Elza [17]3 years ago
4 0
X+2
Replace ab with x
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What is the solution too: R is between Q and S. If RS = 44.6 and SQ = 68.4 find QR
sashaice [31]

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Step-by-step explanation:

3 0
3 years ago
In a lottery game, each ticket cost $3. You have a 10/1000 probability of winning
taurus [48]

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Step-by-step explanation:

6 0
2 years ago
First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

\int x ln(5+x)dx

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

\int (U-5) ln(U)dU

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

\int (pq')=pq-\int qp'

so we must define p, q, p' and q':

p=ln U

p'=\frac{1}{U}dU

q=\frac{U^{2}}{2}-5U

q'=U-5

and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

notice how all the constants were combined into one big constant C.

7 0
3 years ago
1. At the gym on Monday, Larry is told to up his weight on the bench-press by 15% from last week. Last week he was bench-pressin
QveST [7]

Answer:

300 lbs

Step-by-step explanation:

We know that Larry bench pressed 200 lbs last week, and that he is supposed to increase by 15%. We know that any number times one is that same numbers. That means a number that is increaseing has to be greater than 1. So, we have to convert 15% into a decimal. That is 0.15. That plus one is 1.15. Now we just have to multiply 1.15 with 200. We get 300.

3 0
2 years ago
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