I can't do the domain and range but here are the function answers:
1)N
2)N
3)Y
4)N
5)Y
6)Y
7)N
8)N
9)Y
I hope that helped. Sorry I couldn't do the other parts.
Answer:
25.9%
Step-by-step explanation:
Since, the actual dimensions of the cylinder is not given we can assume the some dimension to explain the problem
Let us assume the dimension of the cylinder be
radius= 3in
height= 5 in
The expression for the total surface area of a cylinder is
T. S. A. =2πrh+2πr^2
Let us plug in the values to to find TSA
T. S. A. =2×3.14×3×5+2×3.14×3^2
Solving we get
T. S. A. =94.26+56.556
T. S. A. =150.816 in^2
Now let us find the error
we know that error % is calculated as
%error= [actual value-expected value/expected value]×100
%error= [190 -150.816/150.816]×100
%error= [39.184/150.816]×100
%error= 0.259×100
%error= 25.9%
Answer:44+1 in the equation for this problem
Step-by-step explanation:
Answer:
y = 17x-67
Step-by-step explanation:
The one point form of line also called slope point form is given by
where (x1, y1) is the point and m is slope
Given: (x1, y1) = (4,1) and m= 17
Substituting these values in above equation to find equation in point-slope form
(y-1)=17(x-4)
y-1 = 17x-68
y = 17x-67
the point -slope form of equation y = 17x-67
