Answer
given,
Electric field,E = 490 N/C
time, t = 54 ns
for electron
Mass of electron me = 9.1 x 10⁻³¹ kg
Charge of electron e = -1.6 x 10⁻¹⁹ C
electrostatic force
F = E q
F = 490 x 1.6 x 10⁻¹⁹
F = 784 x 10⁻¹⁹ N
now, using newton second law
a = 8.62 x 10¹² m/s²
using equation of motion
v = u + a t
v = 0 + 8.62 x 10¹² x 54 x 10⁻⁹
v = 4.65 x 10⁵ m/s
velocity of electron is equal to v = 4.65 x 10⁵ m/s
For Proton
Mass mp = 1.67 x 10⁻²⁷ kg
Charge p = 1.6 x 10⁻¹⁹ C
Electric field E = 490 V/C
from above solution
F = 784 x 10⁻¹⁹ N
now, acceleration
a = 4.69 x 10¹⁰ m/s²
using equation of motion
v = u + a t
v = 0 + 4.69 x 10¹⁰ x 54 x 10⁻⁹
v = 4.65 x 10³ m/s
velocity of electron is equal to v = 4.65 x 10³ m/s
The correct answer is option A, 3.528 N
In this question the water has nothing to do, the gravity always pull the object with the same magnitude irrespective of the medium.
The force of gravity is calculated as
F=0.09*4000*9.8
=3.528 N
Answer:
Publishing results of research projects in peer-reviewed journals enables the scientific and medical community to evaluate the findings themselves. It also provides instructions so that other researchers can repeat the experiment or build on it to verify and confirm the results.
Answer:
The velocity will be v = 165.83[m/s]
Explanation:
This is a problem where the definition of kinetic energy can be applied, which can be determined with the following equation.
![E_{k}=\frac{1}{2}*m*v^{2}\\ where:\\m = mass = 80000[kg]\\v = velocity [m/s]\\E_{k}= kinetic energy [J]=1100000000[J]\\Replacing:\\v=\sqrt{\frac{2*E_{k} }{m} } \\v=\sqrt{\frac{2*1100000000 }{80000} }\\v=165.83[m/s]](https://tex.z-dn.net/?f=E_%7Bk%7D%3D%5Cfrac%7B1%7D%7B2%7D%2Am%2Av%5E%7B2%7D%5C%5C%20%20%20where%3A%5C%5Cm%20%3D%20mass%20%3D%2080000%5Bkg%5D%5C%5Cv%20%3D%20velocity%20%5Bm%2Fs%5D%5C%5CE_%7Bk%7D%3D%20kinetic%20energy%20%5BJ%5D%3D1100000000%5BJ%5D%5C%5CReplacing%3A%5C%5Cv%3D%5Csqrt%7B%5Cfrac%7B2%2AE_%7Bk%7D%20%7D%7Bm%7D%20%7D%20%5C%5Cv%3D%5Csqrt%7B%5Cfrac%7B2%2A1100000000%20%7D%7B80000%7D%20%7D%5C%5Cv%3D165.83%5Bm%2Fs%5D)
To solve this question, we use the wave equation which is:
C=f*λ
where:
C is the speed;
f is the frequency;
λ is the wavelength
So in this case, plugging in our values in the problem. This will give us:
C = 261.6Hz × 1.31m
= 342.696 m/s is the answer.
