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melamori03 [73]
3 years ago
6

Mr.marquez had 123 eggs in a refrigerator in his restaurant.he put 32 more cartons of eggs in the refrigerator each carton conta

ined 18 eggs wich of these is the best estimate of the number of eggs mr.marquez now has his refrigerator
Mathematics
1 answer:
Reil [10]3 years ago
8 0
Mr. Marquez has about 720 eggs.
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6. – 4y + 8x = 32 for y
MatroZZZ [7]

Answer:

The answer is: y=2x−8

Step-by-step explanation:

Step 1: Add -8x to both sides.

8x−4y+−8x=32+−8x

−4y=−8x+32

Step 2: Divide both sides by -4.

−4y−4=−8x+32−4

y=2x−8

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3 years ago
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What is the numerator of the fraction equivalent to 3\5 that has a denominator of 30
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Well, the numerator is the number on top, so in the fraction 3/5, 3 is the numerator. To find the equation with a denominator of 30 that is equivalent, find what the difference is. 30/5 = 6. So now, multiply the numerator by 6. 6 * 3 = 18. The new fraction is 18/30. The numerator is 18. Hope this helps!
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9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?
SSSSS [86.1K]

Answer:

Part 4) r=84\ units

Part 9) sin(\theta)=-\frac{\sqrt{5}}{3}

Part 10) sin(\theta)=-\frac{9\sqrt{202}}{202}

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

C=2\pi r

using proportion

\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}

simplify

\frac{r}{180^o}=\frac{56}{120^o}

solve for r

r=\frac{56}{120^o}(180^o)

r=84\ units

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

cos^2(\theta)+sin^2(\theta)=1

we have

cos(\theta)=-\frac{2}{3}

substitute the given value

(-\frac{2}{3})^2+sin^2(\theta)=1

\frac{4}{9}+sin^2(\theta)=1

sin^2(\theta)=1-\frac{4}{9}

sin^2(\theta)=\frac{5}{9}

square root both sides

sin(\theta)=\pm\frac{\sqrt{5}}{3}

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

sin(\theta)=-\frac{\sqrt{5}}{3}

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?    

see the attached figure to better understand the problem

In the right triangle ABC of the figure

sin(\theta)=\frac{BC}{AC}

Find the length side AC applying the Pythagorean Theorem

AC^2=AB^2+BC^2

substitute the given values

AC^2=11^2+9^2

AC^2=202

AC=\sqrt{202}\ units

so

sin(\theta)=\frac{9}{\sqrt{202}}

simplify

sin(\theta)=\frac{9\sqrt{202}}{202}

Remember that      

The point (11,-9) lies in Quadrant IV

then      

The value of sin(∅) is negative

therefore

sin(\theta)=-\frac{9\sqrt{202}}{202}

5 0
3 years ago
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