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4 years ago

___________ of electromagnetic radiation is visible to the human eye. All A narrow portion The white color The dark colo

Physics

2 answers:

pickupchik [31]4 years ago

4 0

The answer is B) <span>A narrow portion. </span>

Nonamiya [84]4 years ago

3 0

Answer:

A narrow portion

Explanation:

Electromagnetic radiation are formed of electromagnetic waves. These electromagnetic waves include radio waves, microwaves, infrared waves, visible light, ultraviolet waves, X-rays, gamma rays. From all these different frequencies of lights only visible light is visible from human eyes. Visible light acquire very small section of electromagnetic waves,

So, a narrow portion of electromagnetic radiation is visible to the human eye.

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2. The water is then heated to its boiling point. Calculate the specific latent heat of

Law Incorporation [45]

Answer:

2465 J/g

Explanation:

The amount of energy required to boil a sample of water already at boiling point is given by

$Q=m\lambda_v$

where

m is the mass of the water sample

$\lambda_v$ is the specific latent heat of vaporization of water

In this problem, we know

$Q=813,600 J$

$m = 330 g$

Solving the equation for $\lambda_v$ , we find

$\lambda_v = \frac{Q}{m}=\frac{813600}{330}=2465 J/g$

6 0

3 years ago

Your teacher had not exercised since the beginning of distance learning. She decided to exercise by walking in the park. The par

Lesechka [4]

A) 6000 m

B) 0 m

C) 3.33 m/s

D) 0 m/s

Explanation:

In physics, distance is a scalar quantity that represents the total length of the path covered by an object during its motion.

Being a scalar quantity, it has no direction, but only a magnitude (so, a number + its units).

The distance covered by a body can be calculated by adding together all the lengths of all the motion of the body.

In this problem, the teacher walks in the partk, starting at position A, then walking around the park 5 times and returning to the original position.

The park has a rectangular shape 200 m x 400 m, so the perimeter of the park is:

$p=200+400+200+400=1200 m$

The teacher covers the perimeter 5 times, so the total distance she covered is:

$d=5p=5\cdot 1200 =6000 m$

Displacement, instead, is a vector quantity that connects the initial position to the final position of the motion of an object.

Being a vector, it has both a magnitude and a direction, where:

- The magnitude is equal to the length of the vector, so it corresponds to the shortest distance in a straight line between the initial and final position

- The direction goes from the initial position to the final position

In this problem:

- The teacher starts her motion at position A

- The teacher ends her motion at position A

So, the distance between the initial and final position is zero:

$d=x_A -x_A = 0$

And therefore, the displacement is zero.

The average speed of an object is a scalar quantity telling us how fast an object is moving, regardless of its direction of motion.

Being a scalar quantity, it has only a magnitude, and no direction.

The average speed is given by the equation:

$v=\frac{d}{t}$

where

d is the distance covered by the object

t is the time elapsed

In this problem we have:

d = 6000 m is the distance covered by the teacher

t = 30 min = 1800 s is the time elapsed

Therefore, the average speed is:

$v=\frac{6000}{1800}=3.33 m/s$

The average velocity of an object is a vector quantity telling us how fast an object is moving but also its direction of motion.

Being a vector, it has both a magnitude and a direction, where:

- The direction corresponds to the direction of the displacement

- The magnitude is given by the formula:

$v=\frac{d}{t}$

where

d is the displacement of the object

t is the time elapsed

In this problem:

d = 0 is the displacement of the teacher

t = 1800 s is the time elapsed

Therefore, the average velocity is zero:

$v=\frac{0}{1800}=0 m/s$

7 0

3 years ago

A comet of mass 1.20 × 10¹⁰kg moves in an elliptical orbit around the Sun. Its distance from the Sun ranges between 0.500 AU and

irina [24]

The eccentricity of its orbit is $U=-2.13 \times 10^{17} \mathrm{~J} .\end{aligned}$

Mass is a physical body's total amount of matter. It also serves as a gauge for the body's inertia or resistance to acceleration (change in velocity) in the presence of a net force. The strength of an object's gravitational pull to other bodies is also influenced by its mass.
The kilogram is the SI unit of mass (kg). In science and technology, a body's weight in a given reference frame is the force that causes it to accelerate at a rate equal to the local acceleration of free fall in that frame.
For instance, a kilogram mass weighs around 2.2 pounds at the surface of the planet. However, the same kilogram mass would weigh just about 0.8 pounds on Mars and about 5.5 pounds on Jupiter.
An object's mass is a crucial indicator of how much stuff it contains. Weight is a measurement of an object's gravitational pull. It is influenced by the object's location in addition to its mass. As a result, weight is a measurement of force.

The length of the semi-major axis is calculated as follows:

where $, $G=6.67 \times 10^{-1} \mathrm{~m}^3 / \mathrm{kgs}$$

$M=1.99 \times 10^{30} \mathrm{~kg}=$ mass of sur

$m=1.20 \times 10^{10} \mathrm{~kg}$ - a mass of the comet

$\begin{aligned}\therefore \quad \text { At aphelion, } r &=50 \times U \\&=50 \times 1.496 \times 10^{11} \mathrm{~m} . \\U=-\frac{6.67 \times 10^{-11} \times \mathrm{m} 1.99 \times 10^{30} \times 1.20 \times 10^{10}}{50 \times 1.496 \times 10^{11}} \\U=-2.13 \times 10^{17} \mathrm{~J} .\end{aligned}$

$U=-2.13 \times 10^{17} \mathrm{~J} .\end{aligned}$

To learn more about mass, refer to:

brainly.com/question/3187640

#SPJ4

4 0

2 years ago

If you swing a bucket of water fast enough in a vertical circle, at the highest point the water does not spill out. This happens

amm1812

Answer:

True

Explanation:

If we swing a bucket of water fast enough in a vertical circle the water does not spill out even at the top-most position of the bucket. This happens because the centrifugal force acting away from the center in a circular motion neutralizes or overcomes the gravitational force on the water particles.

<u>Centrifugal force is mathematically related as:</u>

$F=m.r.\omega^2$