3 years ago

if thanos lost in End Game" what would happend to the gountlet and who would take over the world with it?????

2 answers:

7 0

If Thanos lost the Avengers would most likely destroy the infinity stones so that no one else gets a hold of that power, just like Thanos did when he won.

AleksandrR [38]3 years ago

3 0

Have you seen Endgame?

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a radio antenna broadcasts a 1.0 MHz radio wav e with 21 kW of power. Assume that the radiation is emitted uniformly in all dire

My name is Ann [436]

Answer:

$I=2.67\times 10^{-6}\ W/m$

Explanation:

Given that,

Frequency of a radio antenna is 1 MHz

Power, P = 21 kW

We need to find the the waves intensity 25 km from the antenna . The object emits intenisty evenly in all direction. It can be given by :

$I=\dfrac{P}{4\pi r^2}\\\\I=\dfrac{21\times 10^3}{4\pi (25000)^2}\\\\I=2.67\times 10^{-6}\ W/m$

So, the wave intensity 25 km from the antenna is $2.67\times 10^{-6}\ W/m$ .

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3 years ago

What action will slow down the rate of a reaction?

andreyandreev [35.5K]

B. Decreasing surface area of a solid reactant. The more surface area showing, the quicker the reaction rate.

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3 years ago

How did France and Spain use what they learned during the American revolution to benefit their own countries

alexgriva [62]

Spain declared war on Britain as an ally of France, itself an ally of the American colonies, and provided supplies and munitions to the American forces. Beginning in 1776, it jointly funded Roderigue Hortalez and Company, a trading company that provided critical military supplies.

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3 years ago

An object accelerates 13.0 m/s2 when a force of 4.4 newtons is applied to it. What is the

velikii [3]

Answer:

0.3384 N

Explanation:

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mass = force / acceleration

mass = 4.4 / 13

mass = 0.3384 N

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3 years ago

Calculate the magnitude of the maximum orbital angular momentum Lmax for an electron in a hydrogen atom for states with a princi

erica [24]

Answer:

L_max= 0

Explanation:

The formula for magnitude of maximum orbital angular momentum is given by

$L_{max}= \sqrt{l(l+1)\bar{h}}$

l= orbital quantum number

l= n-1

n= shell number or principal quantum number

for n=1 , l=0

therefore, $L_{max}= \sqrt{0(0+1)\bar{h}}$

L_max= 0

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3 years ago