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suter [353]
3 years ago
7

An athlete rotates a 1.00-kg discus along a circular path of radius 1.09 m. The maximum speed of the discus is 17.0 m/s. Determi

ne the magnitude of the maximum radial acceleration of the discus.
Physics
1 answer:
kaheart [24]3 years ago
8 0

Answer:

a= 289 m/s²  

Explanation:

Given that

mass , m =1 kg

Radius of the path ,R= 1.09 m

The maximum speed ,V= 17 m/s

Lets take the maximum acceleration = a

The radial acceleration is given as

a= \dfrac{V^2}{R}

V=Velocity

R=Radius of the circular path

Now by putting the values in the above equation we get

a= \dfrac{17^2}{1}\ m/s^2

a= 289 m/s²

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Answer:

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B)

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to calculate the angular speed w we can use\alpha=\frac{\omega _{f}-\omega _{i}}{t _{f}-t _{i}}\\\\\omega_{f}=\alpha t_{f}=(3.52\frac{rad}{s^2})(3.6)=12.68\frac{rad}{s}

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C) We can use our result in B)

\alpha=3.52\frac{rad}{s^2}

I hope this is useful for you

regards

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