20 g O2 x 1 mol O2/32 g O = 0.625 mol O2
The correct answer to the problem is 0.193 which is three significant figures.
<h3>What are significant figures?</h3>
The term significant figures has to do with the figures that have a mathematical meaning. We know that the result has to correspond to the highest number of significant figures.
Hence, If we multiply 0.34 x 0.568 the result ought to be recorded as 0.193 which is three significant figures.
Learn more about significant figures:brainly.com/question/14804345
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Answer:
the wax is a nonpolar substance that will not mix with polar water
Explanation:
Water is polar by due to the uneven distribution of charge between the hydrogen and oxygen. T=This automatically eliminates options 3 and 4.
Wax on the other hand is a non polar substance. Due to this non polar characteristic, it would not dissolve in water. The correct option is;
- the wax is a nonpolar substance that will not mix with polar water
The reaction for the combustion of methane can be expressed as follows.
CH4 + 2O2 --> CO2 + 2H2O
We solve first for the amount of carbon dioxide in moles by dividing the given volume by 22.4L which is the volume of 1 mole of gas at STP.
moles of CO2 = (5.6 L) / (22.4 L/1 mole)
moles of CO2 = 0.25 moles
Then, we can see that every mole of carbon dioxide will need 1 mole of methane
moles methane = (0.25 moles CO2) x (1 moles O2/1 mole CO2)
= 0.25 moles CH4
Then, multiply this by the molar mass of methane which is 16 g/mole. Thus, the answer is 4 grams methane.
H2O is the Bronsted-Lowry base because it accepts the hydrogen ion to become H3O after the reaction is complete.
