Answer:
The class of this compound is <u>aldehyde or ketone (i).</u>
Explanation:
Absorption peak at 1720 cm-1 shows the presence of a carbonyl group, possibly an aldehyde or ketone with C=O bond.
Further information on molecular formula would be required for structural elucidation.
Answer:
8.62 g of Hydrogen
Solution:
Molar mass of CH₄O (Methanol) is 32 g.mol⁻¹.
It means,
32 g of CH₄O contains = 4 g of Hydrogen
Then,
69 g of CH₄O will contain = X g of Hydrogen
Solving for X,
X = (69 g × 4 g) ÷ 32 g
X = 8.62 g of Hydrogen
Answer:
1.8g/cm³
Explanation:
Density is defined as the ratio of the mass of a substance and the space this subtance occupies. It is usually given in g/cm³.
The mass of the block is 30g.
The volume this mass occupies is 1.5cm × 4.8cm × 2.3cm = 16.56cm³.
The density is:
30g / 16.56cm³ =
<h3>1.8g/cm³</h3>
Answer:
The liquid level will rise in Side A and drop in Side B.
Step-by-step explanation:
The membrane is impermeable to sucrose, but permeable to sucrose and water.
<u> Side A </u> <u> Side B </u>
2 M sucrose 1 M sucrose
1 M glucose 2 M glucose
(a) Ignoring osmotic effects
The glucose will diffuse spontaneously from the side with higher concentration to that of lower concentration until equilibrium is established. There is no change in volume on either side.
At this point, we have
<u> Side A </u> <u> Side B </u>
2 M sucrose 1 M sucrose
1.5 M glucose 1.5 M glucose
=====
(b) With osmotic effects
The solute concentration on Side A is greater than on Side B.
Water will diffuse into Side A.
The liquid level will rise in Side A and drop in Side B.