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larisa86 [58]
3 years ago
15

which shape has a larger area: a rectangle that is 7 inches by 3/4 inch, or a square with side length of 2 1/2 inches? show your

reasoning.
Chemistry
2 answers:
Nitella [24]3 years ago
6 0

Answer:

Square.

Explanation:

The surface formulae for a rectangle and a square are, respectively:

A_{r} = w\cdot h

A_{s} = l^{2}

The surfaces are computed herein:

A_{r} = (7\,in)\cdot \left(\frac{3}{4}\,in\right)

A_{r} = \frac{21}{4}\,in^{2}

A_{s} = \left(\frac{5}{2}\,in\right)^{2}

A_{s} = \frac{25}{4}\,in^{2}

Since A_{s} > A_{r}, the square has the largest area.

Sveta_85 [38]3 years ago
5 0

The rectangle has an area of- 5.25

and the square has an area of - 6.25

So the square has a larger area

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AysviL [449]

<u>Answer:</u> The \Delta H_f for HCN (g) in the reaction is 135.1 kJ/mol.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. The equation used to calculate enthalpy change is of a reaction is:

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

2NH_3(g)+3O_2(g)+2CH_4(g)\rightarrow 2HCN(g)+6H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(HCN)})+(6\times \Delta H_f_{(H_2O)})]-[(2\times \Delta H_f_{(NH_3)})+(3\times \Delta H_f_{(O_2)})+(2\times \Delta H_f_{(CH_4)})]

We are given:

\Delta H_f_{(H_2O)}=-241.8kJ/mol\\\Delta H_f_{(NH_3)}=-80.3kJ/mol\\\Delta H_f_{(CH_4)}=-74.6kJ/mol\\\Delta H_f_{(O_2)}=0kJ/mol\\\Delta H_{rxn}=-870.8kJ

Putting values in above equation, we get:

-870.8=[(2\times \Delta H_f_{(HCN)})+(6\times (-241.8))]-[(2\times (-80.3))+(3\times (0))+(2\times (-74.6))]\\\\\Delta H_f_{(HCN)}=135.1kJ

Hence, the \Delta H_f for HCN (g) in the reaction is 135.1 kJ/mol.

8 0
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andreev551 [17]

Answer: The frequency of the wave is 0.5 hertz.

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c = speed of the light in m/s

\lambda = Wavelength of the wave.

Here in question we are given with speed of the infrared light. So, we will replace the value of speed of light(c) from the given value of the speed of the infrared light.

Speed of infrared light = 6 m/s

\nu =\frac{\text{speed of infrared light}}{\lambda }=\frac{6 m/s}{12 m}=0.5 hertz

The frequency of the wave is 0.5 hertz.


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So, all those three laws combined state the relation of pressure, volume, temperature and number of particles of a gas, which is what the ideal gas law does: PV = n RT.
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tangare [24]

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The easiest way to do this is to use a proportion.

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