So for this you need to set the two equations equal to each other. 20+.05x=10+.07x then solve. Subtract .05 from both sides and get 20=10+.02x. Then subtract 10 from the other side and get 10=.02x Isolate x by dividing 10 by .02. This leaves you with the answer of 500 texts.
Answer:
50/96
Step-by-step explanation:
I assume the table is:
![\left[\begin{array}{cc}Result&Total\\1&15\\2&13\\3&16\\4&17\\5&15\\6&20\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7DResult%26Total%5C%5C1%2615%5C%5C2%2613%5C%5C3%2616%5C%5C4%2617%5C%5C5%2615%5C%5C6%2620%5Cend%7Barray%7D%5Cright%5D)
Even numbers are 2, 4, and 6. The total number of times she rolled an even number is 13 + 17 + 20 = 50.
So the probability is 50/96.
Answer: 0.0965
Step-by-step explanation:
This would happen if:
First toss: Here we must have any number that is not 6.
the options are 1, 2, 3, 4, 5 so the probablity is p1 = 5/6
The same happens for the second toss, p2 = 5/6
and for the third one: p3 = 5/6
for the fourth toss, person B must roll a 6, so the probability here is p4 = 1/6
Now, the joint probability is equal to the product of the probabilities for each toss, this is:
P = p1*p2*p3*p4 = (5/6)^3*(1/6) = 0.0965
Answer:
10=y/11-13
We move all terms to the left:
-10-(y/11-13)=0
-y/11+13-10=0
We multiply all the terms by the denominator
-y+13*11-10*11=0
We add all the numbers together, and all the variables
-1y+33=0
We move all terms containing y to the left, all other terms to the right
-y=-33
y=-33/-1
y=+33
