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kolezko [41]
3 years ago
9

The lines 2x-4y=4 and y=2x-3 are A. B. C. Parallel Perpendicular Neither

Mathematics
1 answer:
Airida [17]3 years ago
3 0
The answer is C. Neither
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Step-by-step explanation:

Average is the sum of the items in a data divided by the number of items in the data. The role of average is to determine a representative value for the given set of data. What average refers to in statistics is the arithmetic mean. There are other types of mean as well. Therefore, what we are referring to in this scenario is the arithmetic mean. Therefore, another term should not be used in place of​ average. Therefore, the correct option is

C. The term average is often used in statistics to represent the mean.

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Which is greater 21.798 or 217.98?​
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Step-by-step explanation:

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Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
3 years ago
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